The question is incorrect.
The correct question is:
Three TAs are grading a final exam.
There are a total of 60 exams to grade.
(c) Suppose again that we are counting the ways to distribute exams to TAs and it matters which students' exams go to which TAs. The TAs grade at different rates, so the first TA will grade 25 exams, the second TA will grade 20 exams and the third TA will grade 15 exams. How many ways are there to distribute the exams?
Answer: 60!/(25!20!15!)
Step-by-step explanation:
The number of ways of arranging n unlike objects in a line is n! that is ‘n factorial’
n! = n × (n – 1) × (n – 2) ×…× 3 × 2 × 1
The number of ways of arranging n objects where p of one type are alike, q of a second type are alike, r of a third type are alike is given as:
n!/p! q! r!
Therefore,
The answer is 60!/25!20!15!
Answer: 84 people
Step-by-step explanation:
From the question, 240 people are going to a charity event and 3/5 of the guests have ordered chicken for their meals. This means (3/5 × 240) = 144 people ordered chicken. Since 144 people have ordered, the number of remain people left will be:
= 240 - 144
= 96 people.
Out of the remaining guests which is 96, 12.5% have ordered gluten free meals. This means (12.5% × 96) = 12 ordered gluten free meals.
The people who haven't ordered their meals yet will be:
= 96 - 12
= 84 people.
Yes, I cannot draw a line because this is online. Sorry
All you have to do is substitute all the Xs to and get a final y output.
for example:
if we take the number x is -1 all you do is:
y=-4(-1)+2
y=4+2
y=6
thats the first one done
Answer:
n=2
Step-by-step explanation:
2000 pounds = 1 ton 600000 pounds = X tons Hence X tons = (600000 x 1) ÷ 2000 = 300 tons 3 x 10ⁿ = 300 Hence 3 x 10ⁿ = 3 x 10² Hence n= 2
