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kherson [118]
2 years ago
11

there is 90 5th grade students going on a field trip. each student gives the teacher $9.25 to cover admission to the theater and

for lunch. admission for all of the students will cost $315, and each student will get an equal amount to spend on lunch. how much will each fifth grader get to spend on lunch
Mathematics
1 answer:
Allisa [31]2 years ago
5 0
(9.25x90-315)/90
(832.5-315)/90
517.5/90
5.75
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Three percent of Jennie’s skin cells were burned when she escaped from a fire. If 3.7×10’(of her skin cells were burned then, ho
lora16 [44]

Answer:

The quantity of Jennie's skin cell were not burned is 119.601 × 10^{10}  .

Step-by-step explanation:

Given as :

The percentage of Jennie's skin cell were burned = 3 %

The quantity of Jennie's skin cell were burned = 3.7 × 10^{10}

Let The quantity of Jennie's skin cell were not burned = x

Let Total quantity of whole skin cell = n

<u>Now, According to question</u>

The quantity of Jennie's skin cell were burned = Total quantity of whole skin cell × percentage of Jennie's skin cell were burned

i.e 3.7 × 10^{10} = n × 3 %

Or, 3.7 × 10^{10} = n × \dfrac{3}{100}

Or, n =  3.7 × 10^{10} × \dfrac{100}{3}

Or, n = \frac{3.7\times 10^{12}}{3}

i.e n = 1.233 × 10^{12}

Or, Total quantity of whole skin cell = n = 1.233 × 10^{12}

<u>Now, Again</u>

∵ percentage of Jennie's skin cell were burned = 3 %

So, percentage of Jennie's skin cell were not burned = 100 % - 3 % = 97 %

so , The quantity of Jennie's skin cell were not burned = 97 % of Total quantity of whole skin cell

Or, x = \frac{97}{100} × n

Or, x =  \frac{97}{100} × 1.233 × 10^{12}

∴ x = 119.601 × 10^{10}

So, The quantity of Jennie's skin cell were not burned = x = 119.601 × 10^{10}

Hence,  The quantity of Jennie's skin cell were not burned is 119.601 × 10^{10}  . Answer

6 0
2 years ago
According to the Rational Root Theorem, what are all the potential rational roots of f(x) = 15x11 – 6x8 + x3 – 4x + 3?
scoundrel [369]

we have

f(x) = 15x^{11} -6x^{8} + x^{3} - 4x + 3

we know that

<u>The Rational Root Theorem</u> states that when a root 'x' is written as a fraction in lowest terms

x=\frac{p}{q}

p is an integer factor of the constant term, and q is an integer factor of the coefficient of the first monomial.

So

in this problem

the constant term is equal to 3

and the first monomial is equal to 15x^{11} -----> coefficient is 15

So

possible values of p are 1, and\ 3

possible values of q are 1, 3, 5, and\ 15

therefore

<u>the answer is</u>

The all potential rational roots of f(x) are

(+/-)\frac{1}{15},(+/-)\frac{1}{5},(+/-)\frac{1}{3},(+/-)\frac{3}{5},(+/-)1,(+/-)3


3 0
2 years ago
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Umnica [9.8K]
The answer is 25m.
Height = 15
Length = 25
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Lines m and p are perpendicular if the slope of line is 1, 25th what is the slope of line p
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-1 is the opposite reciprical (perpendicular)
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 It is 1/4 (.25), 1/2 (.5)and 7/8 (.875) from least to greatest
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