Part A the coefficient is 20c and 35w, the variable is c and w representing cost and week. and the constant is 23.50.
Part B He would have 503.50 because <span><span>35</span><span>(12)</span></span>+60<span>=<span><span>420x</span>+<span>60+23.50 which would be 503.50
Part C The coefficient of the cost would change because you would be adding a 5 dollar increase!!!!!! done</span></span></span>
Answer:
I believe the answer is the 2nd box{y-2=1/6 (x+10)}, 3rd box{y-1=1/6(x+4)}, and the 5th box{y=1 x/6 +1/3}.
Step-by-step explanation:
To answer this question you would subtract the $250 deductible from $1400. The answer would be $1150 remaining After the deductible. You would then pay 10% of this $1150 for your cost. 0.10 times $1150 =$115. Add the $115 to the $250 deductible and your total cost would be $365.
Answer:
the probability that a sample of the 35 exams will have a mean score of 518 or more is <em> 0.934 </em>or<em> 93.4%</em>.
Step-by-step explanation:
This is s z-test because we have been given a sample that is large (greater than 30) and also a standard deviation. The z-test compares sample results and normal distributions. Therefore, the z-statistic is:
(520 - 518) / (180/√35)
= 0.0657
Therefore, the probability is:
P(X ≥ 0.0657) = 1 - P(X < 0.0657)
where
- X is the value to be standardised
Thus,
P(X ≥ 0.0657) = 1 - (520 - 518) / (180/√35)
= 1 - 0.0657
= 0.934
Therefore, the probability that a sample of the 35 exams will have a mean score of 518 or more is <em>0.934 or 93.4%</em>.
Answer:
A=152
K= -Ln(0.5)/14
Step-by-step explanation:
You can obtain two equations with the given information:
T(14 minutes) = 114◦C
T(28 minutes)=152◦C
Therefore, you have to replace t=14, T=114 and t=28, T=152 in the given equation:
Applying the following property of exponentials numbers in (II):
Therefore 
can be written as 
Replacing (I) in the previous equation:
Solving for k:
Subtracting 190 both sides, dividing by -76:
Applying the base e logarithm both sides:
Ln(0.5)= -14k
Dividing by -14:
k= -Ln(0.5)/14
Replacing k in (I) and solving for A:
Dividing by 0.5
A=152
