Answer:
The price for each kilogram of strawberries is $7.50
Step-by-step explanation:
<u><em>The question is</em></u>
Blues berry farm charges Percy a total of $24.75 for entrance and 2.5 kilograms of strawberries. The entrance fee is $6 and the price for each kilogram of strawberries is constant
Determine the price for each kilogram of strawberries
Let
x ----> the price for each kilogram of strawberries
we know that
The entrance fee plus the price of each kilogram of strawberries multiplied by the number of kilogram of strawberries must be equal to $24.75
so
The linear equation that represent this situation is

solve for x
subtract 6 both sides

divide by 2.5 both sides

therefore
The price for each kilogram of strawberries is $7.50
The choices are the below that can be found elsewhere:
m∠X + m∠Z < 90°
m∠Y > 90°
∠X and∠Y are complementary
m∠X + m∠Y < 90°
Since the given is m<Z > m<X +m<Y and <span>the sum of measure of angles of a triangle is equal 180 degrees so from this result that the last one choice need being true sure so m<X +m<Y < 90°</span>
For this case we have that by definition:
- <em>The terms of a polynomial expression are those that are composed of coefficients and variables separated by signs of addition and subtraction.
</em>
We then have the following expression:

According to the definition, we can conclude that the first term is given by:

Answer:
The first term of the expression is:

Answer:
The probability that it will take more than 10 minutes for the next student to arrive at the library parking lot is 0.0821.
Step-by-step explanation:
The random variable <em>X</em> is defined as the amount of time until the next student will arrive in the library parking lot at the university.
The random variable <em>X</em> follows an Exponential distribution with mean, <em>μ</em> = 4 minutes.
The probability density function of <em>X</em> is:

The parameter of the exponential distribution is:

Compute the value of P (X > 10) as follows:


Thus, the probability that it will take more than 10 minutes for the next student to arrive at the library parking lot is 0.0821.