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2 years ago

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Madison starts with a population of 1,000 amoebas that triples in size every hour for a number of hours, h. She writes the expre

ssion 1,000(3h) to find the number of amoeba after h hours. Tyler starts with a population of 1 amoeba that increases 30% in size every hour for a number of hours, h. He writes the expression (1+0.3)h to find the number of amoeba after h hours. Use the drop-down menus to explain what each part of Madison’s and Tyler’s expressions mean.

2 answers:

gtnhenbr [62]2 years ago

5 0

Answer: The meaning of each term of the Madison’s and Tyler’s expressions is mentioned below.

Step-by-step explanation:

Since, when Madison starts with a population of 1,000 amoebas that triples in size every hour for a number of hours, h.

That is, after 1 hour total number of amoebas = 3×1000 = $3^1\times 1000$

After 2 hour, total number of amoebas = 3×3000= $3^2\times 100$

After 3 hour, total number of amoebas = 3×9000= $3^3\times 1000$

similarly, after h hours, total number of amoebas,

f(h) = $3^h\times 1000$

where, 1000 is the initial population of amoeba 3 is the growth factor of population and f(h) is the population of amoeba after h hours.

Since, when Tyler starts with a population of 1 amoeba that increases 30% in size every hour for a number of hours.

That is, after 1 hour total number of amoebas = $(1+0.3)^1$

After 2 hour, total number of amoebas = $(1+0.3)^2$

After 3 hour, total number of amoebas = $(1+0.3)^3$

Similarly, after h hours, total number of amoebas,

f(h) = $(1+0.3)^h$

Where, 1 is the initial population of amoeba, 0.3 is the growth rate and 1.3 is the growth factor.

Anestetic [448]2 years ago

5 0

The answer is down there on the picture. The other answer isn't totalIy right. I just did it. Please mark Brainliest!

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2 years ago

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a garden plot is to contain 240 sq. ft. if its length is to be 3 times its width,what should its dimensions be?

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W^2=80
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2 years ago

A rectangular board is 1.8 meters long and 1.25 meters wide. What is the area of the board in square millimeters? Do not round y

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Step-by-step explanation:

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1 year ago

Two samples each of size 20 are taken from independent populations assumed to be normally distributed with equal variances. The

Harlamova29_29 [7]

Answer:

$t=\frac{(43.5 -40.1)-(0)}{3.678\sqrt{\frac{1}{20}+\frac{1}{20}}}=2.923$

The degrees of freedom are

$df=20+20-2=38$

And the p value is given by:

$p_v =2*P(t_{38}>2.923) =0.0058$

Since the p value for this cae is lower than the significance level of 0.05 we have enough evidence to reject the null hypothesis and we can conclude that the true means for this case are significantly different

Step-by-step explanation:

When we have two independent samples from two normal distributions with equal variances we are assuming that

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

And the statistic is given by this formula:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}$

Where t follows a t distribution with $n_1+n_2 -2$ degrees of freedom and the pooled variance $S^2_p$ is given by this formula:

$S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}$

The system of hypothesis on this case are:

Null hypothesis: $\mu_1 = \mu_2$

Alternative hypothesis: $\mu_1 \neq \mu_2$

We have the following data given:

$n_1 =20$ represent the sample size for group 1

$n_2 =20$ represent the sample size for group 2

$\bar X_1 =43.5$ represent the sample mean for the group 1

$\bar X_2 =40.1$ represent the sample mean for the group 2

$s_1=4.1$ represent the sample standard deviation for group 1

$s_2=3.2$ represent the sample standard deviation for group 2

First we can begin finding the pooled variance:

$\S^2_p =\frac{(20-1)(4.1)^2 +(20 -1)(3.2)^2}{20 +20 -2}=13.525$

And the deviation would be just the square root of the variance:

$S_p=3.678$

The statistic is givne by:

$t=\frac{(43.5 -40.1)-(0)}{3.678\sqrt{\frac{1}{20}+\frac{1}{20}}}=2.923$

The degrees of freedom are

$df=20+20-2=38$

And the p value is given by:

$p_v =2*P(t_{38}>2.923) =0.0058$

Since the p value for this cae is lower than the significance level of 0.05 we have enough evidence to reject the null hypothesis and we can conclude that the true means for this case are significantly different

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2 years ago

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Answer:

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Step-by-step explanation:

The computation of the probability that a customer neither buys beer nor buys cigars is given below;

Given that, the probabilities are

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And, the customers who purchased beer + cigars be 0.25

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= 0.95

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2 years ago