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2 years ago

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The cost of hiring a surfboard involves an up-front fee plus an hourly rate. Three hours of hire costs $50 and 7 hours costs $90

. Sketch a graph of costs, $C, for t hours of hire using the information given above.

1 answer:

siniylev [52]2 years ago

6 0

Answer:

...... . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

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Zoe had x dollars on Monday.

mel-nik [20]

13.00 I think I don’t know if that correct but that’s what I got

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A company buys paper clips at the rate of $7.50 per box for the first 10 boxes, $5.50 per box for the next 10 boxes, and $3.50 p

BlackZzzverrR [31]

Answer:

46 boxes

Step-by-step explanation:

First 10 boxes can be bought for $7.5*10=75$
Next 10 boxes can be bought for $5.5*10=55$

<em>So for a total of </em><em>20 boxes, </em><em>the cost is $75+55=130$ </em>

<u>We have remaining $221-130=91$ </u>

Each additional box costs 3.5, so for 91 dollars, we can get:

$\frac{91}{3.5}=26$ boxes

So, total $10+10+26=46$ boxes can be bought for $221.00

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2 years ago

The annual salaries of all employees at a financial company are normally distributed with a mean of $34,000 and a standard devia

Alla [95]

Answer:

$z=5$

Step-by-step explanation:

We have been given that the The annual salaries of all employees at a financial company are normally distributed with a mean of $34,000 and a standard deviation of $4,000.

To solve our given problem we will use z-score formula.

$z=\frac{x-\mu}{\sigma}$ where,

$z=\text{z-score}$ ,

$x=\text{Sample score}$ ,

$\mu=\text{Mean}$ ,

$\sigma=\text{Standard deviation}$

Upon substituting our given values in z-score formula we will get,

$z=\frac{54,000-34,000}{4,000}$

$z=\frac{20,000}{4000}$

$z=5$

Therefore, the z-score of a company employee who makes an annual salary of $54,000 is 5.

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2 years ago

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A clothing store offers a free T-shirt when a customer spends $75 or more. Lyndon has already spent $36.95. Which statement best

Jet001 [13]

It would most possibly be 38.05 or less

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2 years ago

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What is the domain of validity for csctheta =start fraction 1 over sine theta end fraction? (1 point) all real numbers all real

dem82 [27]

We know the following relationship:

$csc(\theta)=\frac{1}{sin(\theta)}$

The domain of a function are the inputs of the function, that is, a function $f$ is a relation that assigns to each element $x$ in the set A exactly one element in the set B. The set A is the domain (or set of inputs) of the function and the set B contains the range (or set of outputs).Then applying this concept to our function $csc(\theta)$ we can write its domain as follows:

1. D<span>omain of validity for $csc(\theta)$ :
</span>
$D: \{\theta \in R/ sin(\theta) \neq 0 \} \\ In words: All \ \theta \ that \ are \ real \ values \ except \ those \ that \ makes \ sin(\theta)=0$

When:

$sin(\theta)=0$ ?

when:

$\theta=..., -2\pi,-\pi,0,\pi,\2pi,3pi,...,k\pi$

where k is an integer either positive or negative. That is:

$sin(k\theta)=0 \ for \ k=...,-2,-1,0,1,2,3,...$

To match this with the choices above, the answer is:

<span>"All real numbers except multiples of $\pi$ "

</span>
2. which identity is not used in the proof of the identity $1+cot^{2}(\theta)=csc^{2}(\theta)$ :

This identity can proved as follows:

$sin^2{\theta}+cos^{2}(\theta)=1 \ Dividing \ by \ sin^{2}(\theta) \\ \\ \therefore \frac{sin^2{\theta}}{sin^{2}(\theta)}+\frac{cos^{2}(\theta)}{sin^{2}(\theta)}=\frac{1}{sin^{2}(\theta)} \\ \\ \therefore 1+cot^{2}(\theta)=csc^{2}(\theta)$

The identity that is not used is as established in the statement above:

<span>"1 +cos squared theta over sin squared theta= csc2theta"

Written in mathematical language as follows:

</span> $\frac{1+cos^{2}(\theta)}{sin^{2}(\theta)}=csc^{2}(\theta)$ <span>

</span>

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