answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sp2606 [1]
2 years ago
6

manny's cleaning supply store receives a mixture of 80% detergent and 20% water in 15 gallon buckets. manny would like a mixture

of 60% detergent and 40% water in each 5 gallon bucket. how many gallons of pure water does manny add to each 5 gallon bucket? express your answer as a decimal to the nearest hundredth
Mathematics
1 answer:
Serjik [45]2 years ago
3 0

Answer:

1.25

Thanks,

SunshineMadison101

You might be interested in
A certain article indicates that in a sample of 1,000 dog owners, 610 said that they take more pictures of their dog than of the
lbvjy [14]

Answer:

(a) The 90% confidence interval is: (0.60, 0.63) Correct interpretation is (3).

(b) The 95% confidence interval is: (0.42, 0.46) Correct interpretation is (1).

(c) First, the confidence level in part(b) is <u>more than</u> the confidence level in part(a) is, so the critical value of part(b) is <u>more than</u> the critical value of part(a), Second the <u>margin of error</u> in part(b) is <u>more than</u> than in part(a).

Step-by-step explanation:

(a)

Let <em>X</em> = number of dog owners who take more pictures of their dog than of their significant others or friends.

Given:

<em>X</em> = 610

<em>n</em> = 1000

Confidence level = 90%

The (1 - <em>α</em>)% confidence interval for population proportion is:

CI=\hat p\pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

The sample proportion is:

\hat p=\frac{X}{n}=\frac{610}{1000}=0.61

The critical value of <em>z</em> for a 90% confidence level is:

z_{\alpha/2}=z_{0.10/2}=z_[0.05}=1.645

Construct a 90% confidence interval for the population proportion of dog owners who take more pictures of their dog than their significant others or friends as follows:

CI=\hat p\pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}\\=0.61\pm 1.645\sqrt{\frac{0.61(1-0.61}{1000}}\\=0.61\pm 0.015\\=(0.595, 0.625)\\\approx(0.60, 0.63)

Thus, the 90% confidence interval for the population proportion of dog owners who take more pictures of their dog than their significant others or friends is (0.60, 0.63).

<u>Interpretation</u>:

There is a 90% chance that the true proportion of dog owners who take more pictures of their dog than of their significant others or friends falls within the interval (0.60, 0.63).

Correct option is (3).

(b)

Let <em>X</em> = number of dog owners who are more likely to complain to their dog than to a friend.

Given:

<em>X</em> = 440

<em>n</em> = 1000

Confidence level = 95%

The (1 - <em>α</em>)% confidence interval for population proportion is:

CI=\hat p\pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

The sample proportion is:

\hat p=\frac{X}{n}=\frac{440}{1000}=0.44

The critical value of <em>z</em> for a 95% confidence level is:

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

Construct a 95% confidence interval for the population proportion of dog owners who are more likely to complain to their dog than to a friend as follows:

CI=\hat p\pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}\\=0.44\pm 1.96\sqrt{\frac{0.44(1-0.44}{1000}}\\=0.44\pm 0.016\\=(0.424, 0.456)\\\approx(0.42, 0.46)

Thus, the 95% confidence interval for the population proportion of dog owners who are more likely to complain to their dog than to a friend  is (0.42, 0.46).

<u>Interpretation</u>:

There is a 95% chance that the true proportion of dog owners who are more likely to complain to their dog than to a friend falls within the interval (0.42, 0.46).

Correct option is (1).

(c)

The confidence interval in part (b) is wider than the confidence interval in part (a).

The width of the interval is affected by:

  1. The confidence level
  2. Sample size
  3. Standard deviation.

The confidence level in part (b) is more than that in part (a).

Because of this the critical value of <em>z</em> in part (b) is more than that in part (a).

Also the margin of error in part (b) is 0.016 which is more than the margin of error in part (a), 0.015.

First, the confidence level in part(b) is <u>more than</u> the confidence level in part(a) is, so the critical value of part(b) is <u>more than</u> the critical value of part(a), Second the <u>margin of error</u> in part(b) is <u>more than</u> than in part(a).

4 0
2 years ago
The orbit of the planet Venus is nearly circular. An astronomer develops a model for the orbit in which the sun has coordinates
klio [65]
Since the Venus orbits round the sun, the sun is the center of the circular path of the revolution of the planet, Venus.

Thus, the distance of the planet, Venus fron the sun is given by the distance between the points (0, 0) and (41, 53).

Recall that the distance between two points (x_1, y_1) and (x_2, y_2) is given by d= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Thus, the distance between the points (0, 0) and (41, 53) is given by:

d= \sqrt{(41-0)^2+(53-0)^2}  \\  \\ = \sqrt{41^2+53^2} = \sqrt{1,681+2,809}  \\  \\ = \sqrt{4,490} =67 \ units

Given that each unit of the plane represents 1 million miles, therefore, the distance from the sun to the Venus is 67 million miles.
8 0
2 years ago
Miguel and his brother Ario are both standing 3 meters from one side of a 25-meter pool when they decide to race. Miguel offers
padilas [110]

Answer: 79.4

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Jude has 5 pairs of sunglasses that cost the same in his online shopping cart, then decides to get only 2. Each pair of sunglass
hoa [83]

Answer:

Step-by-step explanation:

5p is the original price

Then 2p is the new price

5p-2p=3p

5 0
2 years ago
A man claims that his lot is triangular, with one side 450 m long and the adjacent side 200 m long. The
harkovskaia [24]

Answer:

545 m

Step-by-step explanation:

Set A = 28º, B as the angle between the 450 m and 200 m side, and C as the remaining angle. Then:

AB = 200 m

BC = 450 m

According to the law of sines:

\frac{450}{sin(28)}=\frac{110}{sin(C)} \\sin(C) = \frac{110}{450}*0.469\\ C= 6.6^o

The remaining angle is then:

B= 180-28-6.6\\B=145.4^o

Applying the law of sines again:

\frac{450}{sin(28)}=\frac{AC}{sin(145.4)} \\AC= \frac{450}{0.469}*0.568\\ AC= 545\ m

To the nearest meter, the other side is 545 meters long.

7 0
2 years ago
Other questions:
  • The solution is n = –2 verified as a solution to the equation 1.4n + 2 = 2n + 3.2. What is the last line of the justification?
    9·1 answer
  • Pada suatu deret geometri diketahui suku ke-3 = 18 dan suku ke-6 = 486. suku pertama pada deret tersebut adalah...
    13·1 answer
  • Peyton is three years younger than Justin. Matt is four times as old as Peyton. If you add together the ages of Justin, Peyton a
    6·2 answers
  • tim drives at an average speed of 80km per hour for 3 hours 45 minutes work out how many kilometres tim drives
    12·1 answer
  • The population of Rock Springs is growing at a constant rate. The expression represents the increase in population in x years.
    14·2 answers
  • A rectangular field is enclosed by 360 feet of fencing. What is the length, in feet, of the field if it’s length is 6 feet more
    7·1 answer
  • For a display, identical cubic boxes are stacked in square layers. Each layer consists of cubic boxes arranged in rows that form
    7·1 answer
  • The picture shows the footprints of a man walking. The pace length P is the distance between the rear of two consecutive footpri
    5·1 answer
  • Wetlands offer a diversity of benefits. They provide a habitat for wildlife, spawning grounds for U.S. commercial fish, and rene
    8·1 answer
  • You want to test the effects of water aerobics on resting heart rate. You decide to test two different levels of exercise (water
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!