Ask question

Ask question

All categories

2 years ago

8

In a certain region, the number of highway accidents increased by 20% over the four years period. How many accidents were there

in 2006 if there were 5102 in 2002? When the % increases, you want the original 100% plus 20%.

1 answer:

erma4kov [3.2K]2 years ago

7 0

Equation:

a = 5120

r = 1 + .2 = 1 . 2

f (n ) = 5120 * 1 . 2^n - 1

N = 4 years

f ( 4 ) 5120 * 1 . 2^4 - 1

5120 * 1 . 2^3

We want to know, The number of Highway Accidents in Four Years.

Answer: 8,847 Highway Accidents total:

Hope that helps!!!!!!!!!!! : )

You might be interested in

A quality control engineer at a potato chip company tests the bag filling machine by weighing bags of potato chips. Not every ba

Ahat [919]

Answer:

$z=\frac{0.21 -0.15}{\sqrt{\frac{0.15(1-0.15)}{100}}}=1.68$

Step-by-step explanation:

Information provided

n=100 represent the random sample taken

X=21 represent the number of bags overfilled

$\hat p=\frac{21}{100}=0.21$ estimated proportion of overfilled bags

$p_o=0.15$ is the value that we want to test

z would represent the statistic

Hypothesis

We need to conduct a hypothesis in order to test if the true proportion of overfilled bags is higher than 0.15.:

Null hypothesis: $p =0.7$

Alternative hypothesis: $p > 0.15$

The statistic for this case is:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

And replacing the info given we got:

$z=\frac{0.21 -0.15}{\sqrt{\frac{0.15(1-0.15)}{100}}}=1.68$

5 0

2 years ago

A machine produces parts that are either defect free (90%), slightly defective (3%), or obviously defective (7%). Prior to shipm

AURORKA [14]

Answer:

(a) 0.0686

(b) 0.9984

(c) 0.0016

Step-by-step explanation:

Given that a machine produces parts that are either defect free (90%), slightly defective (3%), or obviously defective (7%).

Let A, B, and C be the events of defect-free, slightly defective, and the defective parts produced by the machine.

So, from the given data:

P(A)=0.90, P(B)=0.03, and P(C)=0.07.

Let E be the event that the part is disregarded by the inspection machine.

As a part is incorrectly identified as defective and discarded 2% of the time that a defect free part is input.

So, $P\left(\frac{E}{A}\right)=0.02$

Now, from the conditional probability,

$P\left(\frac{E}{A}\right)=\frac{P(E\cap A)}{P(A)}$

$\Rightarrow P(E\cap A)=P\left(\frac{E}{A}\right)\times P(A)$

$\Rightarrow P(E\cap A)=0.02\times 0.90=0.018\cdots(i)$

This is the probability of disregarding the defect-free parts by inspection machine.

Similarly,

$P\left(\frac{E}{A}\right)=0.40$

and $\Rightarrow P(E\cap B)=0.40\times 0.03=0.012\cdots(ii)$

This is the probability of disregarding the partially defective parts by inspection machine.

$P\left(\frac{E}{A}\right)=0.98$

and $\Rightarrow P(E\cap C)=0.98\times 0.07=0.0686\cdots(iii)$

This is the probability of disregarding the defective parts by inspection machine.

(a) The total probability that a part is marked as defective and discarded by the automatic inspection machine

$=P(E\cap C)$

$= 0.0686$ [from equation (iii)]

(b) The total probability that the parts produced get disregarded by the inspection machine,

$P(E)=P(E\cap A)+P(E\cap B)+P(E\cap C)$

$\Rightarrow P(E)=0.018+0.012+0.0686$

$\Rightarrow P(E)=0.0986$

So, the total probability that the part produced get shipped

$=1-P(E)=1-0.0986=0.9014$

The probability that the part is good (either defect free or slightly defective)

$=\left(P(A)-P(E\cap A)\right)+\left(P(B)-P(E\cap B)\right)$

$=(0.9-0.018)+(0.03-0.012)$

$=0.9$

So, the probability that a part is 'good' (either defect free or slightly defective) given that it makes it through the inspection machine and gets shipped

$=\frac{\text{Probabilily that shipped part is 'good'}}{\text{Probability of total shipped parts}}$

$=\frac{0.9}{0.9014}$

$=0.9984$

(c) The probability that the 'bad' (defective} parts get shipped

=1- the probability that the 'good' parts get shipped

=1-0.9984

=0.0016

5 0

2 years ago

The archway of the main entrance of a university is modeled by the quadratic equation y = -x^2 + 6x. The university is hanging a

Galina-37 [17]

So the problem ask on which of the following choices you had is the points should the banner be attached in the archway and the best answer among the choices will be letter C. (1.5, 4.87) and (3.5, 4.37). I hope this will help you and feel free to ask for more.

8 0

3 years ago

Read 2 more answers

Which of the following four items is LEAST like the other three? A, H, I, E

OlgaM077 [116]

The item(letter) that is different from the other three is H.
The other letters(A, I, E) are all vowels, while H is not.

3 0

2 years ago

Read 2 more answers

The Spanish club decides to sell school pins $1.50 each and T-shirts at $6.50 each for a fundraiser. They projects that they wil

Firdavs [7]

Ok so 1.5 is pins and 6.5 is t shirts so you multiply 1.5 x 20 and 6.5 x 5 so for pins= $30 and T-shirts= $32.50 and you times both those numbers by 3 so for pins you get $90 and T-shirts you get $97.50. Finally you add them and get $187.5 so the answer is $187.5 for the project.

5 0

2 years ago