Answer:
The herbicide has no impact on fish
Step-by-step explanation:
Experimental research includes to divide the concerned group 'fishes' here into 'treatment' & 'control' group, to study impact of a treatment. Hypothesis test the statistical significance of propositions. Null hypothesis signifies no impact, alternate hypothesis signifies impact.
Let averages enzyme level of treatment & control be Xt & Xc
- Null Hypothesis [H0] : Xt = Xc, or Xt - Xc = 0
- Alternate Hypothesis [H1] : Xt ≠ Xc, or Xt - Xc ≠ 0
If hypothesis test suggests that there is no significant difference between treatment & control group enzyme level, so we reject H0 & accept H1. It implies that the herbicide has no significant impact on fishes enzymes.
Determine the slope of line AB
m = 5
Determine the slope of the lines from the options
First option: y = 5x + 3, the slope is 5
Second option: y = (1/5)x + 3, the slope is 1/5
Third option: y = -5x + 3, the slope is -5
Fourth option: y = (-1/5)x + 3, the slope is -1/5
Parallel lines are similar in the slope. So the line which is parallel to line AB must have the slope of 5.
The answer is first option.
Complete question is missing, so i have attached it.
Answer:
Percentile is 74th percentile
Step-by-step explanation:
All the lengths given are;
Bear Lengths 36.5 37.5 39.5 40.5 41.5 42.5 43.0 46.0 46.5 46.5 48.5 48.5 48.5 49.5 51.5 52.5 53.0 53.0 54.5 56.8 57.5 58.5 58.5 58.5 59.0 60.5 60.5 61.0 61.0 61.5 62.0 62.5 63.5 63.5 63.5 64.0 64.0 64.5 64.5 65.5 66.5 67.0 67.5 69.0 69.5 70.5 72.0 72.5 72.5 72.5 72.5 73.0 76.0 77.5
The number of lengths (inches) of bears given are 54 in number.
We are looking for the percentile corresponding to 65.5 in.
Looking at the lengths given, since they are already arranged from smallest to highest, let's locate the position of 65.5 in.
The position of 65.5 in is the 40th among 54 lengths given.
If the percentile is P, then;
P% x 54 = 40
P = (40 × 100)/54
P ≈ 74
Average rate of change = [H(100) - H(80)] / (100 - 80)
H(100) = 0.003(100)^2 + 0.07(100) - 0.027 = 0.003(10000) + 0.07(100) - 0.027 = 30 + 7 - 0.027 = 36.973
H(80) = 0.003(80)^2 + 0.07(80) - 0.027 = 0.003(6400) + 0.07(80) - 0.027 = 19.2 + 5.6 - 0.027 = 24.773
Average rate of change = (36.973 - 24.773)/(100 - 80) = 12.2/20 = 0.61
Answer: B