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Alja [10]
2 years ago
12

Linda saves $1.55 every day. Tyron saves $3.90 every day. Linda started saving 3 days earlier than Tyron. On which day will Tyro

n's savings be more than Linda's savings?
Mathematics
2 answers:
madreJ [45]2 years ago
4 0
Step 1: Write the amount of savings in equation
Linda's savings: s=1.55d
Tyron's savings: m=3.90d

Step 2: Add on the extra days to Linda's savings
Linda's savings s=1.55d+3(1.55)

Step 4: Simplify equation
s=1.55d+3(1.55)
s=1.55d+4.66

Step 5: Substitute numbers for d days until Tyron's m savings is greater than Linda's s saving
m=3.90d s=1.55(2)+4.66
m=3.90(2) s=3.10+4.66
m=7.80 s=7.76

On Tyron's second day he will have more money in his savings than Linda does.
l0203
2 years ago
Is the awnser 5?
l02032 years ago
0 0

2 the awnser is basically 2 2 2 2 2 2

l0203
2 years ago
Is the awnser 5? also,
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qwelly [4]

Answer:

h = 13

Step-by-step explanation:

Given the area of a triangle as 84.5 .

The correct value to complete the formula to calculate for the height h is 13 .

Area of a triangle = 1/2 b x h

b = base

h = height

Using the above formula

84.5 = 1/2 x 13 x h

84.5 = 13/2 x h

84.5 = 6.5 x h

84.5 = 6.5h

Divide both sides by 6.5 to get h

84.5/6.5 = 6.5h /6.5

13 = h

h = 13

3 0
2 years ago
David wants to install a fence around his garden. The garden is rectangular and has an area of 240 square feet. One side of the
oee [108]

Answer:

$996

Step-by-step explanation:

The rectangular plot has an area that is the product of its length and width. We are given the width as 12 feet, and the area as 240 ft², so we can find the length from ...

... A = L×W

... 240 ft² = L×(12 ft)

... 240 ft²/(12 ft) = L = 20 ft

Opposite sides of the rectangle are the same length, so the cost of fence for a side of a given length will be the sum of the costs of the opposites sides.

The 12 ft side has one segment that is $18 per foot, and one that is $15 per foot. For the 20 ft sides, both are $15 per foot. Then the total cost can be figured from ...

... (12 ft)·($18/ft + $15/ft) + (20 ft)·($15/ft +$15/ft) = 12·$33 +20·$30 = $996

5 0
2 years ago
True or false? If LM=MP, then M must be the midpoint of LP
Natalija [7]
I think that it's TRUE because it is in the middle when you draw the segment out
7 0
2 years ago
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Mr. Peter charges $2.25 for the usage of laptop for 9 hours. How much Victor needs to pay for 15 hours of usage?
Papessa [141]

Answer:

3.75

Step-by-step explanation:

2.25 divided by 9

= 0.25

then

0.25 * 9

= 3.75

5 0
2 years ago
Read 2 more answers
Square $ABCD$ has area $200$. Point $E$ lies on side $\overline{BC}$. Points $F$ and $G$ are the midpoints of $\overline{AE}$ an
Charra [1.4K]

1. Consider square ABCD. You know that  

A_{ABCD}=AD^2=200,

then

AB=BC=CD=AD=10\sqrt{2}.

2. Consider traiangle AED. F is mipoint of AE and G is midpoint of DE, then FG is midline of triangle AED. This means that

FG=\dfrac{AD}{2}=\dfrac{10\sqrt{2} }{2}=5\sqrt{2}.

3. Consider trapezoid BFGC. Its area is

A_{BFGC}=\dfrac{FG+BC}{2}\cdot h, where h is the height of trapezoid and is equal to half of AB. Thus,

A_{BFGC}=\dfrac{FG+BC}{2}\cdot \dfrac{AB}{2}=\dfrac{5\sqrt{2}+10\sqrt{2}}{2}\cdot \dfrac{10\sqrt{2}}{2}=75.

4.

A_{BFGC}=A_{BFGE}+A_{EGC},\\A_{EGC}=A_{BFGC}-A_{BFGE}=75-34=41.

5. Note that angles EGC and CGD are supplementary and

\sin \angle CGD=\sin \angle EGC.

Then

A_{CGD}=\dfrac{1}{2}CG\cdot CD\cdot \sin \angle CGD=\dfrac{1}{2}CG\cdot EG\cdot \sin \angle CGE=A_{ACG}=41.

Answer: A_{CGD}=41.

8 0
2 years ago
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