This is how the chart will look like:
Kermit Leonard Marlene Norma
Atley
Bradley
Cursen
Drake
1. Drake is Bradley's sister.
2. Cursen is Atley's brother
3. Norma and Drake are not related
<span>4. Kermit is a year older than Bradley
</span>
Drake is a girl (1), but she is not related to Norma(3), So she is Marlene.
1) MARLENE DRAKE
Drake and Bradley are related; Norma is not related to them(3). Norma can either be Atley or Cursen. But, Cursen is Male. So, Norma is NORMA ATLEY
Remaining family names are Bradley and Cursen. Kermit is not a Bradley, so he is KERMIT CURSEN. That leaves LEONARD BRADLEY.
Answer:
< CFE = 40°
Step-by-step explanation:
To better understand the solution, see attachment for the diagram.
Given:
BC parallel to DE
Measure of Arc BD = 58°
Measure of Arc DE = 142°
First step: Draw a diameter that passes through the centre of the circle and name it. In this case, the diameter is line ST.
The line ST divides the arc BD and arc DE into half.
That is:
Arc SC = 1/2(arc BC) =1/2(58)
Arc SC = 29°
Arc TE = 1/2(arc DE) =1/2(142)
Arc TE = 71°
Arc SC + Arc CE + Arc TE = 180° (Sum of angles in a semicircle
29° + Arc CE + 71° = 180°
Arc CE + 100° = 180°
Arc CE = 180-100
Arc CE = 80°
Inscribed angle = 1/2(intercepted angle)
<CFE = 1/2(Arc CE )
<CFE = 1/2(80)
< CFE = 40°
The mileage from the Supermarket to the Library may be calculated using Pythagorean Theorem.
The coordinates of the Library are (7,10) and the coordinates of the Supermarket are (3,7).
So, the distance requested is √ [ (7-3)^2 + (10 - 7)^2 = √[ 4^2 + 3^2 = √ [16 + 9] =
= √25 = 5
So, he runs 5 miles.
And the reimbursement will be $0.50 / mile * 5 mile = $ 2.50.
Answer: option B) $ 2.50
Answer:
a. ∫ xSinx dx
iii. integration by parts
u =x and dv= sinx
b. ∫ x⁴/(1+x³). dx
ii. neither
Long division is an option here before integration is done
c. ∫ x⁴. e^x³. dx
i. substitution
where u = x⁵
d. ∫x⁴ cos(x⁵). dx
i. substitution
where u = x⁵
e. ∫1/√9x+1 .dx
i. substitution
where u = 9x+1
m<ABD = 52 Given
BC bisects <ABD Given
m<ABC = m<CBD Definition of angle bisector.
m<ABC +m<CBD = m<ABD Angle addition postulate.
m<ABC +m<CBD = 52 Substitution
m<ABC + m<ABC= 52 Substitution
2m<ABC = 52 Combining like angles
m<ABC = 26 Division property of equality.
