Answer:
(a) 12π in
(b) 53.5 in
(c) 96 grams
Step-by-step explanation:
In the figure attached, the ornament is shown
(a) four three-quarter circles is equivalent to 4*3/4 = 3 circles. The perimeter of a circle is the total length of the circular portions.
Perimeter of each circle: 2*π*r
The radius is 2 in long, then for 3 circles:
Perimeter = 3*2*π*2 = 12π in
(b) Perimeter of square: 4*side length
The side length of the square is 4 in, then:
Total length of wire needed = 4*4 + 12π = 53.5 in
(c) The wire weighs 1.8 grams per inch, then:
total weight of the ornament = 1.8 grams/in * 53.5 in = 96 grams
Answer:
-There is an outlier at (4.5,15).
-The point (2,60) is an outlier, because it is far away from the rest of the points.
Step-by-step explanation:
An outlier is a data point that is far away from the rest of the data. An outlier does not necessarily represent the extremes in a set of data, as long as it is close to the other points. So, based on the scatter plot, there are two outliers at (2,60) and (4.5,15).
The following statements are true.
There is an outlier at (4.5,15).
The point (2,60) is an outlier because it is far away from the rest of the points.
The Angle-Side Relationships theorem (or triangle parts relationship theorem) states that<span> if one side of a triangle is longer than another side, then the angle opposite the
longer side will have a greater degree measure than the angle opposite the shorter
side.
The converse to the </span>Angle-Side Relationships theorem (or triangle parts relationship theorem) states that if one angle of a triangle has a greater degree measure than
another angle, then the side opposite the greater angle will be longer than the
side opposite the smaller angle.
Thus, from the proof if AB > AC, then m∠C > m∠B by the <span>converse of the triangle parts relationship theorem</span>.
Answer:
Hey there!
We can solve this by multiplying 0.3 by 546, which is about 164.
Hope this helps :)
Answer:
obviously they will produce same output because the elevation of object and image will be same
