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BARSIC [14]
2 years ago
8

(5.81*10^-3)*(8.7*10^10) in scientific notation

Mathematics
1 answer:
GalinKa [24]2 years ago
3 0
5.0547x10^8
Is it's scientific notation.
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leva [86]
The answer would be {(n^5)^2}/{(4*m^3)^2} = { n^{10} }/{16*m^6}
8 0
2 years ago
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What is the area of a circle with a radius of 9.4cm
Contact [7]
A \\ = \pi r ^{2} \\ = 3.14 \times {9.4}^{2} \\ = 277.4504

Answer : Area = 277.45cm^2

Hope this helps. - M
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A ride at an amusement park moves the riders in a circle at a rate of 6.0 m/s. The radius of the ride is 9.0 meters. Which of th
lana [24]

Answer with explanation:

It is given that , ride at an amusement park moves the riders in a circle at a rate of 6.0 m/s.

a=\frac{dv}{dt}=6 m/s

Radius of Circle = 9.0 meters

Acceleration is rate of change of velocity,which will be perpendicular to radius vector.

Also, in terms of mathematics, line from center that is radius , to point of contact that is tangent line ,which is on the circle are perpendicular to each another.

→r(radius vector) ⊥  a(Acceleration vector).

So, In option A, Radius vector is Perpendicular to acceleration of riders.

4 0
2 years ago
All of the students in Ms. Osbourne's class like pizza. Jeff is a student who likes pizza. Therefore, Jeff is a student in Ms. O
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8 0
2 years ago
6.8 Use the Normal approximation. Suppose we toss a fair coin 100 times. Use the Normal approximation to find the probability th
Maru [420]

Answer:

(a) The probability that proportion of heads is between 0.30 and 0.70 is 1.

(b) The probability that proportion of heads is between 0.40 and 0.65 is 0.9759.

Step-by-step explanation:

Let <em>X</em> = number of heads.

The probability that a head occurs in a toss of a coin is, <em>p</em> = 0.50.

The coin was tossed <em>n</em> = 100 times.

A random toss's result is independent of the other tosses.

The random variable <em>X</em> follows a Binomial distribution with parameters n = 100 and <em>p</em> = 0.50.

But the sample selected is too large and the probability of success is 0.50.

So a Normal approximation to binomial can be applied to approximate the distribution of \hat p<em> </em>(sample proportion of <em>X</em>) if the following conditions are satisfied:

  1. np ≥ 10
  2. n(1 - p) ≥ 10

Check the conditions as follows:

 np=100\times 0.50=50>10\\n(1-p)=100\times (1-0.50)=50>10

Thus, a Normal approximation to binomial can be applied.

So,  \hat p\sim N(p,\ \frac{p(1-p)}{n})

\mu_{p}=p=0.50\\\sigma_{p}=\sqrt{\frac{p(1-p)}{n}}=0.05

(a)

Compute the probability that proportion of heads is between 0.30 and 0.70 as follows:

P(0.30

                              =P(-4

Thus, the probability that proportion of heads is between 0.30 and 0.70 is 1.

(b)

Compute the probability that proportion of heads is between 0.40 and 0.65 as follows:

P(0.40

                              =P(-2

Thus, the probability that proportion of heads is between 0.40 and 0.65 is 0.9759.

6 0
2 years ago
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