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2 years ago

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All of the students in Ms. Osbourne's class like pizza. Jeff is a student who likes pizza. Therefore, Jeff is a student in Ms. O

sbourne's class.

1 answer:

faust18 [17]2 years ago

8 0

Whats the question. I need the question to answer.

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The aquarium has 10 more red fish than blue fish. 60 percent of the fish are red. How many blue fish are in the aquarium?

guajiro [1.7K]

Answer:

20 blue fish

Step-by-step explanation:

Number of blue fish = x

Number of red fish = x+10

Red fish = 60% of total = 0.6

Total fish = x+x+10 = 2x+10

0.6 = (x+10)/(2x+10)

Solve for x:

1.2x+6 = x+10

0.2x = 4

x = 20

Hope this helps!

Mark as brainliest :))

7 0

2 years ago

Read 2 more answers

The surface area of an oil spill gets 105% larger every day, represented by the function s(x) = (1.05)x − 1. On the first day, i

ioda

The given scenario above is like a geometric sequence with r or common ratio being 1.05 and the first term being 31 square meters. The nth term of the sequence is calculated through the equation,
A15 = (A1)(r)^(n - 1)
Substituting,
A15 = (31)(1.05)^(15 - 1) = 61.3778 square meter
Therefore, the area covered by the spill after the 15th day is approximately 61.4 square meters.

6 0

2 years ago

It takes 5 carpenters 5 hours to make 5 chairs. How long would it take 100 carpenters to make 100 chairs?

Elza [17]

I hour because, one of the 5 carpenters built one chair in one hour, so one of the 100 carpenters would build one chair in one hour, there are only 95 more carpenters, nothing else different.
Hope I helped!

7 0

2 years ago

Read 2 more answers

The law of cosines is a2+b2-2abcosC=c2 find the value of 2abcosC

quester [9]

Isolating 2abCos(c) on one side of the equation and using the given values of a, b and c we can find the answer to this question as shown below:

$a^{2} + b^{2} -2ab*cos(C)=c^{2} \\ \\ 
2ab *cos(C)= a^{2} + b^{2} - c^{2} \\ \\ 
2ab *cos(C)=2^{2} + 2^{2}- 1^{2} \\ \\ 
2ab*cos(C) = 7$

7 0

2 years ago

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G find the area of the surface over the given region. use a computer algebra system to verify your results. the sphere r(u,v) =

Svetach [21]

Presumably you should be doing this using calculus methods, namely computing the surface integral along $\mathbf r(u,v)$ .

But since $\mathbf r(u,v)$ describes a sphere, we can simply recall that the surface area of a sphere of radius $a$ is $4\pi a^2$ .

In calculus terms, we would first find an expression for the surface element, which is given by

$\displaystyle\iint_S\mathrm dS=\iint_S\left\|\frac{\partial\mathbf r}{\partial u}\times\frac{\partial\mathbf r}{\partial v}\right\|\,\mathrm du\,\mathrm dv$

$\dfrac{\partial\mathbf r}{\partial u}=a\cos u\cos v\,\mathbf i+a\cos u\sin v\,\mathbf j-a\sin u\,\mathbf k$
$\dfrac{\partial\mathbf r}{\partial v}=-a\sin u\sin v\,\mathbf i+a\sin u\cos v\,\mathbf j$
$\implies\dfrac{\partial\mathbf r}{\partial u}\times\dfrac{\partial\mathbf r}{\partial v}=a^2\sin^2u\cos v\,\mathbf i+a^2\sin^2u\sin v\,\mathbf j+a^2\sin u\cos u\,\mathbf k$
$\implies\left\|\dfrac{\partial\mathbf r}{\partial u}\times\dfrac{\partial\mathbf r}{\partial v}\right\|=a^2\sin u$

So the area of the surface is

$\displaystyle\iint_S\mathrm dS=\int_{u=0}^{u=\pi}\int_{v=0}^{v=2\pi}a^2\sin u\,\mathrm dv\,\mathrm du=2\pi a^2\int_{u=0}^{u=\pi}\sin u$
$=-2\pi a^2(\cos\pi-\cos 0)$
$=-2\pi a^2(-1-1)$
$=4\pi a^2$

as expected.

6 0

2 years ago