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harina [27]
2 years ago
5

Playing tennis burns energy at a rate of about 25 kJ/min. Cycling burns energy at about 35kJ/min. Hans exercised by playing tenn

is and then cycling. He exercised for 50 min altogether and used a total of 1450kJ of energy. For how long did he play tennis?
Mathematics
1 answer:
grigory [225]2 years ago
8 0
To answer this, you need to make a systems of equations.

25x + 35y = 1450
x + y = 50 ----> y = 50 - x

25x + 35(50-x) = 1450
25x + 1750 - 35x = 1450
25x - 35x + 1750 = 1450
-10x + 1750 = 1450
- 1750 -1750

-10x = -300
x = 30


He played tennis for 30min


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When solving negative one over five -1/5 (x − 25) = 7, what is the correct sequence of operations
aleksandr82 [10.1K]

The solution would be like this for this specific problem:

 

\left( { - 5} \right)
\cdot \left( { - \frac{1}{5}} \right) \cdot \left( {x - 25} \right) = 7 \cdot
\left( { - 5} \right)

 

 

\left( { - 5} \right)
\cdot \left( { - \frac{1}{5}} \right) = 1

 

The correct sequence of operations when solving negative one over five (x − 25) = 7 would be multiply each side by −5, and adding 25 to each side.

5 0
2 years ago
A process engineer is implementing a quality assurance system on a breakfast cereal production line. A new sensor is installed o
nataly862011 [7]

Answer:

0.2%

Step-by-step explanation:

The given parameters are;

The percentage of product within the correct range = 95%

The percentage of the times the sensor reject boxes of incorrect weight = 98%

The percentage of the times the company reject boxes with correct weight = 1%

\begin{array}{cccc}&P&N&T\\P&TP&0.9&90\\N&FP&9.8&10\end{array}

We have, FN = 0.9, TN = 9.8, TP = 90 - 0.9 = 89.1, FP = 10 - 9.8 = 0.2

FNR = FN/(FN + TP) = 0.9/(0.9 + 89.1) = 0.01

FPR = 0.2/(0.2 + 9.8) = 0.02

TPR = 89.1/(89.1 + 0.9) = 0.99

TNR = 9.8/(9.8 + 0.2) = 0.98

P(C/A) = TPR × P(C)/((TPR × P(C) + FPR×(1 - P(C)))

Where;

P(C/A) = The probability that a correct weight package is accepted

∴ P(C/A) = 0.99*0.9/(0.99*0.9 + 0.02*0.1) ≈ 0.99776

The probability that a correctly weighed package is rejected, P(C/R), is given as follows;

P(C/R) = 1 - P(C/A)

∴ P(C/R) ≈ 1 - 0.99776 = 0.00224 ≈ 0.2%

The probability that a correctly weighed package is rejected, P(C/R) ≈ 0.2%

5 0
2 years ago
f1(x) = ex, f2(x) = e−x, f3(x) = sinh(x) g(x) = c1f1(x) + c2f2(x) + c3f3(x) Solve for c1, c2, and c3 so that g(x) = 0 on the int
eimsori [14]

Answer:

(C1, C2, C3) = (K, K, -2K)

For K in the interval (-∞, ∞)

Step-by-step explanation:

Given

f1(x) = e^x

f2(x) = e^(-x)

f3(x) = sinh(x)

g(x) = 0

We want to solve for C1, C2 and C3, such that

C1f1(x) + C2f2(x) + C3f3(x) = g(x)

That is

C1e^x + C2e^(-x) + C3sinh(x) = 0

The hyperbolic sine of x, sinh(x), can be written in its exponential form as

sinh(x) = (1/2)(e^x + e^(-x))

So, we can rewrite

C1e^x + C2e^(-x) + C3sinh(x) = 0

as

C1e^x + C2e^(-x) + C3(1/2)(e^x + e^(-x)) = 0

So we have

(C1 + (1/2)C3)e^x + (C2 + (1/2)C3)e^(-x) = 0

We know that

e^x ≠ 0, and e^(-x) ≠ 0

So we must have

(C1 + (1/2)C3) = 0...........................(1)

and

(C2 + (1/2)C3) = 0..........................(2)

From (1)

2C1 + C3 = 0

=> C3 = -2C1.................................(3)

From (2)

2C2 + C3 = 0

=> C3 = -2C2................................(4)

Comparing (3) and (4)

2C1 = 2C2

=> C2 = C1

Let C1 = C2 = K

C3 = -2K

(C1, C2, C3) = (K, K, -2K)

For K in the interval (-∞, ∞)

3 0
2 years ago
The formula for finding the interest on a loan is I = prt. Jack borrows $2,000 for 2 years at a rate of 2%. How much interest wi
bearhunter [10]

i = p \times r \times t
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3 0
2 years ago
Read 2 more answers
Kayleigh babysat for 11 hours this week. That was 5 fewer than 2/3 as many hours as she babysat last week, h. Write an equation
lukranit [14]

Answer: The answer is \textup{x}=\dfrac{2}{3}\textup{h}-5.


Step-by-step explanation: Given that Kayleigh babysat for 11 hours the present week. Also, this was 5 less than two-third of the number of hours she babysat last week, which is represented by 'h'.

We are to write an equation to represent the number of hours she babysat each week.

So, for that, let 'x' be the number of hours she babysat this week. Then, according to the question, we can write

\textup{x}=\dfrac{2}{3}\textup{h}-5.

Also, it is given that

\textup{x}=11.

Therefore,

11=\dfrac{2}{3}\textup{h}-5\\\\\Rightarrow \dfrac{2}{3}\textup{h}=16\\\\\Rightarrow \textup{h}=24.

Hence, using the above relation, we can find the number oh hours Keyleigh babysat each week.

Thus, the required equation is

\textup{x}=\dfrac{2}{3}\textup{h}-5,

where, 'x' and 'h' are the number of hours she sat this week and last week respectively.

 


4 0
2 years ago
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