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Pepsi [2]
1 year ago
5

A company manufactures Handband, a wireless activity tracker. There are initial start up costs involved. Additionally, the compa

ny spends a certain amount of money to manufacture each Handband. The cost of manufacturing h Handbands is given by the function, C(h) = 21h + 15000
Which of the following statements are true? Check all that apply.

Mathematics
1 answer:
Mashutka [201]1 year ago
8 0

Answer:

1. 21 represents the cost of manufacturing one handband.

3. The initial start up cost is $15000.

5. The company spends $57000 to manufacture 2000 handbands.

Step-by-step explanation:

We are given the cost function for manufacturing 'h' amount of handbands and it is provided that there was initial start up costs involved.

Now, as the cost function is given by, C(h) = 21h + 15000.

We can see that the initial start up cost is $15000.

As, 'h' is the number of handbands being made. So, 21h in C(h) is the cost of manufacturing 'h' handbands.

Therefore, 21 is the cost of manufacturing one handband.

Since, C(h) = 21h + 15000.

Substituting h = 2000, we get,

C(2000) = 21×2000 + 15000.

i.e. C(2000) = 42000 + 15000.

i.e. C(2000) = 57000.

The company spends $57000 to manufacture 2000 handbands.

Since, we are provided with only cost function, we can not talk about the profit.

Hence, option 1, 3 and 5 are correct.

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Answer:

The magnitude of the necessary lifting force is 7.95N

Step-by-step explanation:

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Force = 2.00105×123^2/3810 = 30273.89/3810 = 7.95N

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1 year ago
Faelyn grouped the terms and factored the GCF out of the groups of the polynomial 6x4 – 8x2 + 3x2 + 4. Her work is shown.
Y_Kistochka [10]
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2 years ago
Read 2 more answers
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KATRIN_1 [288]
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The y-intercept of (0, 2) is 2.

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2 years ago
In ADEF, f = 610 inches, e = 590 inches and ZE=70°. Find all possible values of ZF,
Elina [12.6K]

Answer:

"76°" is the appropriate solution.

Step-by-step explanation:

Please find attachment of the diagram according to the given query.

The given values are:

In ΔDEF,

f = 610 inches

e = 590

∠E = 70°

∠F = ?

By using the law of sines, we get

⇒  \frac{Sin E}{e} =\frac{Sin  F}{f}

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⇒  \frac{Sin70^{\circ}}{590} =\frac{SinF}{610}

On applying cross multiplication, we get

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now,

⇒  F=Sin^{-1}(0.971546608)

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