Answer:
volume of trapezoidal prism = 15x^2 cubic units
Step-by-step explanation:
First, area of the trapezoidal bases.
Parallel sides measure x and 2x, for an average of 1.5x.
Height = x
Area of trapezoidal base = 1.5x*x = 1.5x^2
Volume of prism = area base * height
(length does not matter, height does)
= 1.5x^2 * 10 = 15x^2
Answer:
524.96 − 32.50 + x ≥ 500
Amount need to deposit = $7.54
Step-by-step explanation:
Given:
Amount in checking account = $524.96
Maintain amount = $500
Amount of check = $32.50
Find:
Amount need to deposit
Computation:
Assume, amount need to deposit = x
So,
For avoiding fee
524.96 − 32.50 + x ≥ 500
x = 7.54
Amount need to deposit = $7.54
Answer:
3rd graph down
Step-by-step explanation:
greens are x and carrots are y in my equations
2x - y >= 3
x + 2y < 4
The first equation is solid and will highlight everything to the right of it because it is a >
the second is dashed and will highlight everything to the left of it because it is a <
the only 2 graphs that show this are 1 and 3
looking at the points you can see that the points for the solid line are both the same so ignore those and go to the dashed lined ones.
on the first graph the points are (0,4)
plugging those into our equation gives us 0 + 2*4 <4
or 8<4 which doesnt make sense making 3 the correct graph
(sorry my answer wasnt posting so i had to start over and make it less detailed, but comment if you need any explanation)
Answer:
Greatest number of flowers that can be used in a bouquet is 8.
Step-by-step explanation:
In this question greatest number of flowers used in a bouquet will be decided by the "Greatest Common Factor" of the numbers of the flowers given.
So, factors of 16 = 1×2×2×2×2
Factors of 8 = 1×2×2×2
Factors of 32 = 1×2×2×2×2×2
Common factors = 1×2×2×2
Greatest Common Factor of these numbers will be = 1×2×2×2 = 8.
Therefore, greatest number of flowers that could be in a bouquet is 8.
The height of the ball when it is 5 meters away from Jake to the nearest whole number is 160 meters:
h=-.625*5(5-56)=159.375 meters exact.