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Katarina [22]
2 years ago
7

Consider the experiment of rolling a pair of dice. Suppose that we are interested in the sum of the face values showing on the d

ice. (a) How many sample points are possible? (Hint: use the counting rule for multiple-step experiments.) (b) List the sample points. There to sum the face values of a pair of dice to 2. There to sum the face values of a pair of dice to 3. There to sum the face values of a pair of dice to 4. There to sum the face values of a pair of dice to 5. There to sum the face values of a pair of dice to 6. There to sum the face values of a pair of dice to 7. There to sum the face values of a pair of dice to 8. There to sum the face values of a pair of dice to 9. There to sum the face values of a pair of dice to 10. There to sum the face values of a pair of dice to 11. There to sum the face values of a pair of dice to 12. (c) What is the probability of obtaining a value of 5? (d) What is the probability of obtaining a value of 8 or greater? (e) Because each roll has six possible even values (2, 4, 6, 8, 10, and 12) and only five possible odd values (3, 5, 7, 9, and 11), the dice should show even values more often than odd values. Do you agree with this statement? Explain. This statement correct because P(odd) = and P(even) = . (f) What method did you use to assign the probabilities requested? classical method empirical method subjective method relative frequency method
Mathematics
1 answer:
den301095 [7]2 years ago
7 0

Answer:

a.) 21

b.)

c.) 2/21

d.) 3/7

e.) Yes

f.) relative frequency method.

Step-by-step explanation:

Possible sample space if we are interested in only the sum becomes :

[1,1] [1,2] [1,3] [1,4] [1,5] [1,6]

[2,2] [2,3] [2,4] [2,5] [2,6]

[3,3] [3,4] [3,5] [3,6]

[4,4] [4,5] [4,6]

[5,5] [5,6]

[6,6]

a) there are 21 sample points.

b.) sample points to give sum of "2" = [1,1]

Sample points to give sum of "3" = [1,2]

Sample points to give sum of "4" = [1,3] [2,2]

Sample points to give sum of "5" = [1,4] [2,3]

Sample points to give sum of "6" = [1,5] [2,4] [3,3]

Sample points to give sum of "7" = [1,6] [2,5] [3,4]

Sample points to give sum of "8" = [2,6] [3,5] [4,4]

Sample points to give sum of "9" = [3,6] [4,5]

Sample points to give sum of "10" = [4,6] [5,5]

Sample points to give sum of "11" = [5,6]

Sample points to give sum of "12" = [6,6]

c.) probability of obtaining a value of 5 = favourable outcome/possible outcome = 2/21

d.) Probability of obtaining a value of 8 or greater = 9/21 = 3/7.

e.) Yes I agree with the statement because its only logical that since there are more values of even numbers than odd numbers, then we will see more of even than odd numbers.

f.) relative frequency method was used to assign the probabilities because we are dealing with the number of occurrence of a particular sum value.

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A probability calculator is required on this problem; answer to six decimal places. Suppose we will spin the wheel pictured 400
KiRa [710]

Answer:

P(90< X< 110)= P(\frac{90-80}{8}

And we can find this probability with this difference:

P(90< X< 110)=P(z

And we can find the real value with the following excel code using the binomial distribution:

"=BINOM.DIST(110,400,0.2,TRUE)-BINOM.DIST(89,400,0.2,TRUE)"

And we got 0.118 a very close value from the value obtained using the normal approximation

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=400, p=0.2)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

We need to check the conditions in order to use the normal approximation.

np=400*0.2=80 \geq 10

n(1-p)=400*(1-0.2)=320 \geq 10

So we see that we satisfy the conditions and then we can apply the approximation.

If we appply the approximation the new mean and standard deviation are:

E(X)=np=400*0.2=80

\sigma=\sqrt{np(1-p)}=\sqrt{400*0.2(1-0.2)}=8

So then we can approximate the random variable as X \sim N(\mu = 80, \sigma = 8)

And we want this probability:

P(90< X< 110)

We can use the z score formula given by:

z = \frac{x -\mu}{\sigma}

And replacing we got:

P(90< X< 110)= P(\frac{90-80}{8}

And we can find this probability with this difference:

P(90< X< 110)=P(z

And we can find the real value with the following excel code using the binomial distribution:

"=BINOM.DIST(110,400,0.2,TRUE)-BINOM.DIST(89,400,0.2,TRUE)"

And we got 0.118 a very close value from the value obtained using the normal approximation

8 0
2 years ago
Find the area of the triangle with the given measurements. Round the solution to the nearest hundredth if necessary. A = 46°, b
horrorfan [7]
We will use the law of cosines
<span>side a² = b² + c² -2bc • cos(A)
</span><span>side a² = 729 + 196 -2*27*14 * cos (46)
</span><span>side a² = 925 -(756 * 0.69466)
</span>side a² = <span><span>399.83704 </span>
side a = </span><span><span><span>19.995925585 </span> </span> </span>
We could round that to 20
a = 20 b = 27 c =14

We can calculate a triangle's area when we know all 3 sides by using Heron's Formula
<span>area = square root (s • (s - a) • (s - b) • (s - c))

where s is the semi-perimeter </span>
semi-perimeter<span> = (side a + side b + side c) ÷ 2</span>
s = (20 + 27 + 14) / 2
s = 30.5
Now we use Heron's Formula
area = square root (s • (s - a) • (s - b) • (s - c))
area = square root (30.5 • (<span>30.5 - 20) • (</span><span>30.5 - 27) • (</span><span>30.5 - 14))</span>
area = square root (30.5 • (10.5) • (3.5) • (<span>16.5))</span>
<span>area = square root (18494.4375)
</span> <span><span><span>area = 135.9942553934  </span> </span> </span>which rounds to
136 square feet
Source:
http://www.1728.org/triang.htm

 




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2 years ago
Your band is one of 8 bands competing at the battle of the bands. The order of the performances is determined at random. The fir
lorasvet [3.4K]

Answer:

1.79 %.

Step-by-step explanation:

you have to calculate the probability of a series of events before you can calculate the final probability.

The first event is that the band plays on Friday.

If there are 8 bands, but only 5 play on Friday, then the probability that they will play on Friday is

5/8

Now, the second event that they are the last ones is 1/5, since they are 5 bands.

Therefore the probability that they will play on Saturday and last is

5/8 * 1/5 = 1/8

Now, for the rival band it would be, knowing that on Friday there is already a quota assigned and one band less, the probability that they will play that day is

4/7

as they play before the other group, it would be 1/4, as there is already a quota assigned.

The final probability would then be:

4/7 * 1/4 = 1/7

Now the probability that the band gives the last performance on Friday night and your rival band performs immediately before them, is:

1/8 * 1/7 = 0.0179

That is 1.79 %.

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2 years ago
Please Please Help Ne In This Math homework?!?!?!
weeeeeb [17]
6 is yes because they have the same angles and lengths while 7 is no because the angles are not the same
8 0
2 years ago
The Census Bureau reports that 82% of Americans over the age of 25 are high school graduates. A survey of randomly selected resi
SVETLANKA909090 [29]

Answer:

a) Mean = 1030; Standard deviation = 12.38.

b) The county result is unusually high.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.

(a) Find the mean and standard deviation for the number of high school graduates in groups of 1210 Americans over the age of 25.

This first question is a binomial propability distribution.

We have a sample of 1210 Amricans, so n = 1210.

The mean of the sample is 1030.

The probability of a success is \pi = \frac{1030}{1210} = 0.8512.

The standard deviation of the sample is s = \sqrt{n\pi(1-\pi)} = \sqrt{1210*0.8512*0.1488} = 12.38

(b) Is that county result of 1030 unusually high, or low, or neither?

The first step is find the zscore when X = 1030.

Then we find the pvalue of this zscore.

If this pvalue is bigger than 0.95, the county result is unusually high.

If this pvalue is smaller than 0.05, the county result is unusually low.

Otherwise, it is neither.

The national mean is 82%. So,

\mu = 0.82(1210) = 992.2

Z = \frac{X - \mu}{\sigma}

Z = \frac{1030 - 992.2}{12.38}

Z = 3.05

Z = 3.05 has a pvalue of 0.9989.This means that the county result is unusually high.

4 0
2 years ago
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