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Rzqust [24]
2 years ago
7

Now let the figure show a scale drawing of a park with the largest dimension equal to 63 meters. What is the scale

Mathematics
1 answer:
Strike441 [17]2 years ago
5 0
Let
 x = scale
 For this case you should count how many divisions there are in the longest dimension.
 14
 Then, as the longest dimendion of the park is 63 meters then, the scale is
 14x = 63
 x = 63/14
 x = 4.5
 answer
 the scale is 4.5m
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Answer:

1/128 kilograms.

Step-by-step explanation:

First, multiply 16 and 4 to get 64. Since the weight of the box is 1/2 (or 0.5), so we have each cookie's weight at 1/128. Please mark this "brainliest" (the crown) if you like this answer!

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8 0
1 year ago
Darlene wrote this proof of the identity (x + y)2 - (x - y)2 = 4xy. Which of the following is a justification for Step 3 of her
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Solution:

we are given that

Darlene wrote this proof of the identity (x + y)2 - (x - y)2 = 4xy.

we have been asked to find

Which of the following is a justification for Step 3 of her proof?

Step 3 of her proof is

Step 3: (x^2 + xy + xy + y^2) - (x^2 - xy - xy + y^2) = (x^2 + 2xy + y2) - (x^2 - 2xy + y^2)

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C. Combining like terms

7 0
2 years ago
Joe receives an average of 780 emails in his personal account and 760 emails in his work account each month. After changing his
Semmy [17]

Answer:

702 emails

Step-by-step explanation:

<h2>This problem bothers on depreciation of value, in this context it is Joe's email that has depreciated by 10%.</h2>

Given data

Average personal emails received monthly = 780 emails

Average work emails received monthly= 760 emails

     

      We are required to solve for the new amount of emails Joe will be receiving after changing his address, to find this value we need to solve for the depreciation of his personal mails.

      After solving for the depreciation , we then need to subtract the depreciation from the initial number of mails to get the new number of mails.

let us solve for 10% depreciation.

depreciation= \frac{10}{100} *780\\depreciation=0.1*780= 78 emails

The new number of mails

= initial number of mail- depreciation\\ =780-78= 702 emails

Joe will be receiving an average of 702 emails in his personal account monthly

7 0
1 year ago
The principal is collecting data to determine how many graduation tickets will be needed by students at the next graduation. She
nadya68 [22]

<em>*</em><em>100% Correct answers</em>

Question 1

A movie theater was putting up their posters in the frames they had installed on the wall for upcoming attractions. They have 8 new movie posters and only 4 installed frames along the wall to hang them. So, they wont be able to use them all. In how many different ways can they arrange the new movie posters in the frames?

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8 0
2 years ago
Read 2 more answers
The random variable X is normally distributed with mean 82 and standard deviation 7.4. Find the value of q such that P(82 − q &l
mezya [45]
P(82 - q < x < 82 + q) = 0.44
P(x < 82 + q) - P(82 - q) = 0.44
P(z < (82 + q - 82)/7.4 - P(z < (82 - q - 82)/7.4) = 0.44
P(z < q/7.4) - P(z < -q/7.4) = 0.44
P(z < q/7.4) - (1 - P(z < q/7.4) = 0.44
P(z < q/7.4) - 1 + P(z < q/7.4) = 0.44
2P(z < q/7.4) - 1 = 0.44
2P(z < q/7.4) = 1.44
P(z < q/7.4) = 0.72
P(z < q/7.4) = P(z < 0.583)
q/7.4 = 0.583
q = 0.583 x 7.4 = 4.31
8 0
1 year ago
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