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AnnZ [28]
1 year ago
8

If you have 60 million barrels and you have 14% kerosene and 34% gasoline what is the total production of gasoline and kerosene

combined barrels
Mathematics
2 answers:
Drupady [299]1 year ago
6 0
48% or 48/100 only in percents and fractions
In-s [12.5K]1 year ago
4 0

Answer:

Total production of gasoline and kerosene combined 48% that is 28.8 million.

Step-by-step explanation:

Total production = 60 million barrels

Gasoline = 34%

Kerosene = 14%

Total combined = 34% + 14% = 48%

48% of 60 million = 0.48 × 60 = 28.8 million

Total production of gasoline and kerosene combined 48% that is 28.8 million.

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A game involves rolling a fair six-sided die. If the number facing upward on the die is a whole number multiple of three, the pl
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Answer:

E = 0 x (4/6) + 60 x (1/6) + 120 x (1/6)  = 30

Step-by-step explanation:

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1 year ago
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A flat circular plate has the shape of the region x squared plus y squared less than or equals 1x2+y2≤1. the​ plate, including t
vredina [299]

You're looking for the extreme values of x^2+3y^2+13x subject to the constraint x^2+y^2\le1.

The target function has partial derivatives (set equal to 0)

\dfrac{\partial(x^2+3y^2+13x)}{\partial x}=2x+13=0\implies x=-\dfrac{13}2

\dfrac{\partial(x^2+3y^2+13x)}{\partial y}=6y=0\implies y=0

so there is only one critical point at \left(-\dfrac{13}2,0\right). But this point does not fall in the region x^2+y^2\le1. There are no extreme values in the region of interest, so we check the boundary.

Parameterize the boundary of x^2+y^2\le1 by

x=\cos u

y=\sin u

with 0\le u. Then t(x,y) can be considered a function of u alone:

t(x,y)=t(\cos u,\sin u)=T(u)

T(u)=\cos^2u+3\sin^2u+13\cos u

T(u)=3+13\cos u-2\cos^2u

T(u) has critical points where T'(u)=0:

T'(u)=-13\sin u+4\sin u\cos u=\sin u(4\cos u-13)=0

(1)\quad\sin u=0\implies u=0,u=\pi

(2)\quad4\cos u-13=0\implies\cos u=\dfrac{13}4

but |\cos u|\le1 for all u, so this case yields nothing important.

At these critical points, we have temperatures of

T(0)=14

T(\pi)=-12

so the plate is hottest at (1, 0) with a temperature of 14 (degrees?) and coldest at (-1, 0) with a temp of -12.

4 0
1 year ago
Anna and Veronica are on the opposite sides of a tower of 160 meters height. They measure the angle of elevation of the top of t
MAXImum [283]

Answer: The distance between the girls is 362.8 meters.

Step-by-step explanation:

So we have two triangle rectangles that have a cathetus in common, with a length of 160 meters.

The adjacent angle to this cathetus is 40° for Anna, then the opposite cathetus (the distance between Anna and the tower) can be obtained with the relationship:

Tan(A) = opposite cath/adjacent cath.

Tan(40°) = X/160m

Tan(40°)*160m = 134.3 m

Now, we can do the same thing for Veronica, but in this case the angle adjacent to the tower is 55°

So we have:

Tan(55°) = X/160m

Tan(55°)*160m = X = 228.5 m

And we know that the girls are in opposite sides of the tower, so the distance between the girls is equal to the sum of the distance between each girl and the tower, then the distance between the girls is:

Dist = 228.5m + 134.3m = 362.8m

8 0
1 year ago
Susan works as a hostess where she makes $8.75 per hour. She also babysits and earns $10.00 per hour. Last week she made $165.00
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Answer:

6 hours as a babysitter and 12 hours as a hostess

5 0
1 year ago
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The true average diameter of ball bearings of a certain type is supposed to be 0.5 in. A one-sample t test will be carried out t
Naily [24]

Answer:

Option C - Do not reject the null hypothesis. There is not sufficient evidence that the true diameter differs from 0.5 in

Step-by-step explanation:

We are given;

n = 15

t-value = 1.66

Significance level;α = 0.05

So, DF = n - 1 = 15 - 1 = 14

From the one-sample t - table attached, we can see that the p - value of 0.06 at a t-value of 1.66 and a DF of 14

Now, since the P-value is 0.06,it is greater than the significance level of 0.05. Thus we do not reject the null hypothesis. We conclude that there is not sufficient evidence that the true diameter differs from 0.5 in.

8 0
1 year ago
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