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kotykmax [81]
2 years ago
5

The mayor of Gilbert, AZ, randomly selects 300 of its residents for a survey while the mayor of Camp Verde, AZ, randomly selects

100 of its residents and asks them the same question. Both surveys show that 15% of the residents of each town want Arizona to start using daylight savings like most of the rest of the country. If the confidence level for both surveys is 95% (z*-value 1.96), then which statement is true? The margin of error for the Camp Verde survey will be the size of the margin of error for the Gilbert survey. The margin of error for the Camp Verde survey will be between and the size of the margin of error for the Gilbert survey. The margin of error for the Camp Verde survey will be three times greater than the margin of error for the Gilbert survey. The margin of error for the Camp Verde survey will be between one and three times as great as the margin of error for the Gilbert survey. Mark this and return
Mathematics
2 answers:
vazorg [7]2 years ago
8 0

Answer:

The margin of error for the Camp Verde survey will be between one and three times as great as the margin of error for the Gilbert survey.

Step-by-step explanation:


Ostrovityanka [42]2 years ago
5 0
I don’t think you wrote it correct but anyway I think the answer to your question is statement number 1
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michelle wants to borrow $4,500. bank a will lend michelle the money at a simple annual interest rate of 9% for 6 years. bank b
Ahat [919]
Bank A:
A = 4500(1 + (0.09 × 6)) = 6930 
A = $ 6,930.00

The total amount accrued, principal plus interest,
from simple interest on a principal of $ 4,500.00
at a rate of 9% per year.
<span>for 6 years is $ 6,930.00.
</span>
Bank B: 
A = 4500(1 + (0.11 × 4)) = 6480 
A = $ 6,480.00

The total amount accrued, principal plus interest,
from simple interest on a principal of $ 4,500.00
at a rate of 11% per year
<span>for 4 years is $ 6,480.00.
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So bank B would charge the least amount of interest.
5 0
1 year ago
Read 2 more answers
a 12 foot tall building casts on 8 foot long long shadow. how long of a shadow will a 5 foot tall women have
grin007 [14]
This is just a basic proportion. 5/8 = x/12. So the 5 foot tall women would have a 7.5 foot shadow.
7 0
2 years ago
At a Psychology final exam, the scores are normally distributed with a mean 73 points and a standard deviation of 10.6 points. T
USPshnik [31]

Answer:

The score that separates the lower 5% of the class from the rest of the class is 55.6.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question:

\mu = 73, \sigma = 10.6

Find the score that separates the lower 5% of the class from the rest of the class.

This score is the 5th percentile, which is X when Z has a pvalue of 0.05. So it is X when Z = -1.645.

Z = \frac{X - \mu}{\sigma}

-1.645 = \frac{X - 73}{10.6}

X - 73 = -1.645*10.6

X = 55.6

The score that separates the lower 5% of the class from the rest of the class is 55.6.

3 0
1 year ago
in 2016 the average Raleigh driver spent 18 hours in traffic jams, which accounted for 6% of their total driving time. How many
castortr0y [4]

Answer: 300 hrs

The time spent behind the wheel by the average Raleigh driver in 2016 is  300 hrs

Step-by-step explanation:

Given that;

Raleigh driver spent 18 hours in traffic jams

And it accounts for 6% of their total driving time

Now

let total driving time be = x hrs

so

6% of total driving time = 18 hrs

6/100 × x = 18hrs

6x = 1800 hrs

x = 1800/6

x = 300 hrs

∴ The time spent behind the wheel by the average Raleigh driver in 2016 is  300 hrs

5 0
2 years ago
Lynn works as a part-time vendor selling necklaces for $15 each and bangles for $10 each. She needs to earn a minimum of $300 pe
timofeeve [1]

A,B,C,D i.e. all statements are true!

<u>Step-by-step explanation:</u>

According to question, Lynn works as a part-time vendor selling necklaces for $15 each and bangles for $10 each. She needs to earn a minimum of $300 per week to cover her expenses. The inequality for above scenario will be :

15x + 10y\geq 300 where, x is number of necklaces & y is number of bangles.

A.

Lynn will meet her goal if she sells 12 bangles and 12 necklaces. i.e. x=12 and y=12 , putting values inequality : 15(12) + 10(12)  = 300 which follows inequality . True statement!

B.

Lynn will meet her goal if she sells 20 bangles and 6 necklaces.

putting values inequality : 15(6) + 10(20) = 290 which follows inequality . True statement!

C.

Lynn will meet her goal if she sells 6 bangles and 12 necklaces. putting values inequality : 15(12) + 10(6) = 240, which follows inequality . True statement!

D.

Lynn will meet her goal if she sells 2 bangles and 18 necklaces.putting values inequality : 15(18) + 10(2)=290, which follows inequality . True statement!

7 0
2 years ago
Read 2 more answers
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