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aniked [119]
2 years ago
11

Mr and Mrs Smith buy tickets for themselves and their children the cost of an adult ticket is 6 pounds more than the cost of a C

hilds ticket the total cost of the six tickets is ?40.50 work out the cost of an adult ticket
Mathematics
1 answer:
abruzzese [7]2 years ago
8 0

Answer: Cost of adult ticket is $10.75.

Step-by-step explanation:

Since we have given that

Total cost of the six tickets = $40.50

Number of adults = 2

Number of children = 4

Let the cost of child's ticket be x

Let the cost of adult's ticket be y

So, According to question,

y=x+6---------(1)\\\\and\\\\2y+4x=\$40.50---------(2)

Put the value of Eq(1) in Eq(2), we get

2y+4x=\$40.50\\\\2(6+x)+4x=40.50\\\\12+2x+4x=40.50\\\\6x=40.50-12\\\\6x=28.5\\\\x=\frac{28.5}{6}\\\\x=\$4.75

So, The cost of child's ticket is $4.75

Hence, the cost of adult's ticket will be

y=x+6=4.75+6=\$10.75

Therefore, Cost of adult ticket is $10.75.

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The lifespans of lions in a particular zoo are normally distributed. The average lion lives 12.512.512, point, 5 years; the stan
zaharov [31]

This question was not written properly

Complete Question

The lifespans of lions in a particular zoo are normally distributed. The average lion lives 12.5 years; the standard deviation is 2.4 years. Use the empirical rule (68-95-99.7\%)(68−95−99.7%) to estimate the probability of a lion living between 5.3 to 10. 1 years.

Answer:

Thehe probability of a lion living between 5.3 to 10. 1 years is 0.1585

Step-by-step explanation:

The empirical rule formula states that:

1) 68% of data falls within 1 standard deviation from the mean - that means between μ - σ and μ + σ.

2) 95% of data falls within 2 standard deviations from the mean - between μ – 2σ and μ + 2σ.

3) 99.7% of data falls within 3 standard deviations from the mean - between μ - 3σ and μ + 3σ.

Mean is given in the question as: 12.5

Standard deviation : 2.4 years

We start by applying the first rule

1) 68% of data falls within 1 standard deviation from the mean - that means between μ - σ and μ + σ.

μ - σ

12.5 -2.4

= 10.1

We apply the second rule

2) 95% of data falls within 2 standard deviations from the mean - between μ – 2σ and μ + 2σ.

μ – 2σ

12.5 - 2 × 2.4

12.5 - 4.8

= 7.7

We apply the third rule

3)99.7% of data falls within 3 standard deviations from the mean - between μ - 3σ and μ + 3σ.

μ - 3σ

= 12.5 - 3(2.4)

= 12.5 - 7.2

= 5.3

From the above calculation , we can see that

5.3 years corresponds to one side of 99.7%

Hence,

100 - 99.7%/2 = 0.3%/2

= 0.15%

And 10.1 years corresponds to one side of 68%

Hence

100 - 68%/2 = 32%/2 = 16%

So,the percentage of a lion living between 5.3 to 10. 1 years is calculated as 16% - 0.15%

= 15.85%

Therefore, the probability of a lion living between 5.3 to 10. 1 years

is converted to decimal =

= 15.85/ 100

= 0.1585

8 0
2 years ago
In a certain country, a letter up to 1 ounce requires postage in the amount of $0.42, and each additional ounce (or fraction of
kati45 [8]
The answer is $7.14 is wunt josiah pay
8 0
2 years ago
Read 2 more answers
The distribution of annual profit at a chain of stores was approximately normal with mean \mu = \$66{,}000μ=$66,000mu, equals, d
Pepsi [2]

Answer:

The closest to the maximum profit is  x = \$ 83682

Step-by-step explanation:

From the question we are told that

  The  mean is  \mu  =  \$66,000

   The standard deviation is  \sigma  = \$ 21000

   The percentage of profit is  20%

Generally the closest to the maximum annual profit at a store where the executives conducted an audit is mathematically evaluated  as follows

     P(X >  x ) =  0.20

=>  P(X >  x ) = P(\frac{X -x}{\sigma }  >  \frac{x -66000}{21000} ) =  0.20

From the z-table  the z-score for  0.20  is  

    z-score =  0.842

So

     \frac{x -66000}{21000}  = 0.842

=>   x = \$ 83682

4 0
2 years ago
SAT Writing scores are normally distributed with a mean of 491 and a standard deviation of 113.A university plans to send letter
Sholpan [36]

Answer:

z=1.405

And if we solve for a we got

a=491 +1.405*113=649.765

So the value of height that separates the bottom 92% of data from the top 8% is 649.765.  

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the scores of a population, and for this case we know the distribution for X is given by:

X \sim N(491,113)  

Where \mu=491 and \sigma=113

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.08   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.92 of the area on the left and 0.08 of the area on the right it's z=1.405. On this case P(Z<1.405)=0.92 and P(z>0.92)=0.08

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=1.405

And if we solve for a we got

a=491 +1.405*113=649.765

So the value of height that separates the bottom 92% of data from the top 8% is 649.765.  

6 0
2 years ago
A spherical scoop of ice cream is placed on top of a hollow ice cream cone. the scoop and cone have the same radius. the ice cre
noname [10]
The figure shown below illustrates the problem.

The volume of the empty cone is
V₁ = (1/3) π r²h

The volume of the sphere is
V₂ = (4/3) π r³

Because the melted ice cream completely fills the cone, therefore
V₁ = V₂
(1/3) π r² h = (4/3) π r³
Divide each side by (1/3) π r².
h = 4r

Answer:
The height of the cone is 4 times greater than the radius f the cone.

5 0
2 years ago
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