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Nikitich [7]
1 year ago
7

Suppose you are told that a distribution is said to be approximately normal because outliers have skewed the data. List the poss

ible ways outliers can skew an approximately normal distribution and what effect they can have.
Mathematics
1 answer:
andrew-mc [135]1 year ago
8 0

Answer:

Step-by-step explanation:

Outline are values which are entirely different from those remaining values in a data set. These extreme values can skew an approximately normal distribution by skewing the distribution in the direction of the outliers and this makes it difficult for the data set to be analyzed.

Its effect is such that the mean becomes extremely sensitive to extreme outliers making it possible that the mean is this not a representative of the population and this theoretically affects the standard deviation.

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I see that your new product is available for 412.50 on the website. How much is it if I buy it in the store? The website is a 25
OverLord2011 [107]

Answer with explanation:

Price of Product on the Website = $ 412.50

It is given that, product is offered at a discount of 25% on the website.

Let actual price of product on the store = $ x

Writing the above statement in terms of equation

→Price at store - Discount= Price at Website

x-\frac{25\times x}{100}=412.50\\\\ \frac{75 x}{100}=412.50\\\\x=\frac{41250}{75}\\\\x=550

Price at store of that Product = $ 550

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2 years ago
What is the answer for(y⁴)³
Natasha2012 [34]
The answer to the problem is y^12
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2 years ago
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Samantha walked 10 miles in 5 hours. What was her walking rate in miles per hour?
Vitek1552 [10]

Answer:

2 miles per hour

Step-by-step explanation:

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2 years ago
Need help <br> -1/2 + (3/4X4/9)=
Agata [3.3K]

Answer:

The correct answer would be negative 1 over 6 also written as -1/6

Step-by-step explanation:

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4 0
1 year ago
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The pH scale measures how acidic or basic a substance is. Lemon juice is said to have a pH of less than 4 and greater than 1.5.
castortr0y [4]

Let's say x is J because it's Lemon Juice.

It's said that the pH of J is less than 4 so: pH(J) < 4 and pH(J) is greater than 1.5 so: pH(J) > 1.5

Now we can construct:

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Or simply:

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We can also write this with an interval:

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r3t40

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