Hiii
all you do is subtract...
534-476=58
58 spots are left.
Hello,
I am going to remember:
y'+3y=0==>y=C*e^(-3t)
y'=C'*e^(-3t)-3C*e^(-3t)
y'+3y=C'*e^(-3t)-3Ce^(-3t)+3C*e^(-3t)=C'*e^(-3t) = t+e^(-2t)
==>C'=(t+e^(-2t))/e^(-3t)=t*e^(3t)+e^t
==>C=e^t+t*e^(3t) /3-e^(3t)/9
==>y= (e^t+t*e^(3t)/3-e^(3t)/9)*e^(-3t)+D
==>y=e^(-2t)+t/3-1/9+D
==>y=e^(-2t)+t/3+k
Hey!
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Solution:
Ratio is 4/1
Add.
4 + 1 = 5
Divide.
150 / 5 = 30
Multiply for Ivan.
30 x 4 = 120
30 x 1 = 30
Check.
120 + 30 = 150
Subtract.
120 - 30 = 90
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Answer:
Ivan has £90 more than Tanya has!
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Hope This Helped! Good Luck!
Answer:
11 inches by 11 inches
Step-by-step explanation:
The dimensions of the original photo were 11 inches by 11 inches.
We are informed that the area of the reduced photo is 64 square inches and that In the equation (x – 3)^2 = 64, x represents the side measure of the original photo.
In order to solve for x, we shall first take square roots on both sides of the equation;
The square root of (x – 3)^2 is simply (x - 3).
The square root of 64 is ±8 but we ignore -8 since the dimensions of any figure must be positive.
Therefore, we have the following equation;
x - 3 = 8
x = 8 + 3
x = 11
The answer is that Jade's chickens laid more eggs. Since Jade's farm includes 9 chickens, which each laid 3 eggs, multiply 9 and 3 and you get 27. Edna's farm has chickens which, in total, laid 23 eggs, leading to Jade's chickens with 27 eggs to be more than the eggs laid by Edna's chickens. :)
