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aliya0001 [1]
2 years ago
15

Each month, Angela budgets $1340 for fixed expenses, $850 for living expenses, and $60 for annual expenses. Her annual net incom

e is $26,760. Which sentence best describes her monthly budget? Explain.
a. it shows a deficit of $20
b. it shows a surplus of $20
c. it shows a deficit of $140
d. it is balanced
Mathematics
2 answers:
Pavlova-9 [17]2 years ago
7 0
1340+850=2190*12=26,280+60=26,340
27,760-26,340=$1420

larisa [96]2 years ago
3 0
Hey there
____________
The correct answer is
Yearly budget= $26,760

Fixed expenses per month= $1340
Fixed expenses per year (1340×12) =$16,080

Living expenses per month= $850
Living expenses per year (850×12)= $10,200

Annual expenses= $60

Add ALL the expenses together.
16,080+10,200+60= $26340

Angela monthly budget is balanced

So the answer is d
_______________
HOPE THIS HELPS you
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From the given graph , we can see that at 4th season, the profit = 15

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2 years ago
Nyoko needs to be at school at 7:45 AM. It takes her 15 minutes to walk to school, 5/12 hour to eat breakfast, 0.7 hour to get d
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So, she wants to be at school at 7.40 (5 mins early)

she needs:

15 mins
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so far: 40 mins

then 0.7 and 0.15: we can add those, since they're in decimals: 0.85.

how many minutes is this?

\frac{85}{100} *60=  \frac{85}{10} *6=\frac{85}{5} *3=\frac{13}{1} *3=39

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6.21!
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2 years ago
In a large population, 82% of the households have cable tv. A simple random sample of 225 households is to be contacted and the
anzhelika [568]

Answer:

The mean of the sampling distribution of the sample proportions is 0.82 and the standard deviation is 0.0256.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For proportions, the mean is \mu = p and the standard deviation is s = \sqrt{\frac{p(1-p)}{n}}

In this problem, we have that:

p = 0.82, n = 225.

So

\mu = 0.82

s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.82*0.18}{225}} = 0.0256

The mean of the sampling distribution of the sample proportions is 0.82 and the standard deviation is 0.0256.

7 0
2 years ago
Read 2 more answers
8.39+(-2.00)+161 <br><br> i got 167.39 but it isnt correct<br> so if yall could help me plsssss
mafiozo [28]
I think it should be 171.39
8 0
2 years ago
Read 2 more answers
The following table shows a portion of a four-year amortization schedule. A 4-year amortization schedule. The loan amount or pri
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Answer:

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8 0
2 years ago
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