Answer: Chuck can paint 65 posts per hour.
Step-by-step explanation:
The data we have here is:
Diana can paint 150 fence posts in a time T
Chuck can pint 130 fence posts in a time T.
In one hour, Diana can paint 10 more fence posts than Chuck.
If D is the hourly rate of Daian, and C is the hourly rate for Chuck, we have:
D = 150/T
C = 130/T
D = C + 10
we can replace the last equation in the first one and geT:
C + 10 =150/T
C = 130/T
Now we can replace the bottom equation in the above one:
130/T + 10 = 150/T
10 = 150/T - 130/T = 20/T
T*10 = 20
T = 20/10 = 2
So T is 2 hours, then whe have:
D = 150post/2hours = 75 posts per hour.
C = 130 posts/2hours = 65 posts per hour.
The paraboloid meets the x-y plane when x²+y²=9. A circle of radius 3, centre origin.
<span>Use cylindrical coordinates (r,θ,z) so paraboloid becomes z = 9−r² and f = 5r²z. </span>
<span>If F is the mean of f over the region R then F ∫ (R)dV = ∫ (R)fdV </span>
<span>∫ (R)dV = ∫∫∫ [θ=0,2π, r=0,3, z=0,9−r²] rdrdθdz </span>
<span>= ∫∫ [θ=0,2π, r=0,3] r(9−r²)drdθ = ∫ [θ=0,2π] { (9/2)3² − (1/4)3⁴} dθ = 81π/2 </span>
<span>∫ (R)fdV = ∫∫∫ [θ=0,2π, r=0,3, z=0,9−r²] 5r²z.rdrdθdz </span>
<span>= 5∫∫ [θ=0,2π, r=0,3] ½r³{ (9−r²)² − 0 } drdθ </span>
<span>= (5/2)∫∫ [θ=0,2π, r=0,3] { 81r³ − 18r⁵ + r⁷} drdθ </span>
<span>= (5/2)∫ [θ=0,2π] { (81/4)3⁴− (3)3⁶+ (1/8)3⁸} dθ = 10935π/8 </span>
<span>∴ F = 10935π/8 ÷ 81π/2 = 135/4</span>
For this question, you need to understand how to divide fractions.First we line up our fractions appropriately:
4/9 ÷ 4/5 = ? (You want to divide 4/9 by 4/5)
4/9 × 5/4 = ? (Now we use the reciprocal of 4/5 and multiply instead of divide)
4 x 5 = 20 and 9 x 4 = 36. (Cross multiply.)
20/36 = 5/9. (Simplify to lowest terms.)
So, 4/9 divided by 4/5 is 5/9!But 5/9 is more than 4/9, so the answer is 0 :PCorrect me if I'm wrong.
Answer:
Pierre operates at a greater power level than Marie.
Marie and Pierre do the same amount of work
Step-by-step explanation:
Mass of crate=60kg
Height of truck bed=1 m
Time=3s
Pierre's work done=
Using formula Work done=mgh
Where m=mass of object
g=Acceleration due to gravity=9.8
Power=
Using the formula
Pierre's power=
Mass of box=2.5Kg
Total number of boxes=24
Total mass of boxes=
Time=2 min=
1 min=60 s
Marie;s work done=
Marie's power=
Pierre operates at a greater power level than Marie.
Marie and Pierre do the same amount of work
