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cupoosta [38]
2 years ago
10

The probability that a professional baseball player will get a hit is 1/3. Calculate the exact probability that he will get at l

east 3 hits in 5 attempts.
Mathematics
1 answer:
Evgesh-ka [11]2 years ago
3 0
It is given here that there is 1/3 probability of professional baseball player will get a hit. Hence if  at least three hits are gained out of 5 attempts, the calculation goes:  5C3* (1/3)^3*(2/3)^2 + 5C4* (1/3)^4*(2/3)^1 +5C5 *<span>(1/3)^5*(2/3)^0 equal to 0.21. </span>
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Candy draws a square design with a side length of x inches for the window at the pet shop. She takes the design to the printer a
Inga [223]

Answer:

This is late, but for anyone else that needs it, it's B. 4x-5

8 0
2 years ago
Read 2 more answers
The amount of time it takes for a student to complete a statistics quiz is uniformly distributed (or, given by a random variable
topjm [15]

Answer:

(A) 0.15625

(B) 0.1875

(C) Can't be computed

Step-by-step explanation:

We are given that the amount of time it takes for a student to complete a statistics quiz is uniformly distributed between 32 and 64 minutes.

Let X = Amount of time taken by student to complete a statistics quiz

So,   X ~ U(32 , 64)

The PDF of uniform distribution is given by;

    f(X) = \frac{1}{b-a} ,  a < X < b      where a = 32 and b = 64

The CDF of Uniform distribution is P(X <= x) = \frac{x-a}{b-a}

(A) Probability that student requires more than 59 minutes to complete the quiz = P(X > 59)

   P(X > 59) = 1 - P(X <= 59) = 1 - \frac{x-a}{b-a} = 1 - \frac{59-32}{64-32} = 1-\frac{27}{32} = 0.15625

(B) Probability that student completes the quiz in a time between 37 and 43 minutes = P(37 <= X <= 43)  = P(X <= 43) - P(X < 37)

    P(X <= 43) = \frac{43-32}{64-32} = \frac{11}{32} = 0.34375

    P(X < 37) = \frac{37-32}{64-32} = \frac{5}{32} = 0.15625

    P(37 <= X <= 43) = 0.34375 - 0.15625 = 0.1875

(C) Probability that student complete the quiz in exactly 44.74 minutes

     = P(X = 44.74)

The above probability can't be computed because this is a continuous distribution and it can't give point wise probability.

3 0
2 years ago
Please help!!
rusak2 [61]
ANSWER TO QUESTION 1

The set of natural numbers that are factors of 20 are natural numbers that divides 20 exactly without a remainder.

These natural numbers are;

{1,2,4,5,10,20}

Therefore the correct answer is D

ANSWER TO QUESTION 2

Given that the universal set U has elements

{1,2,3,4,5,6,7,8,9,10}

and the set P also has elements

{2,4,6,8,10}

The elements of P' are the elements that are in the universal set but are not in set P.

These elements are;

{1,3,5,7,9}

The correct answer is C

ANSWER TO QUESTION 3

The distance is given by the absolute value equation

d=|130-25t|

If the is 15 feet away then d=15

This implies that;

15=|130-25t|

We now split the absolute value sign to obtain,

15=130-25t

or

-15=130-25t

We now solve for t to obtain;

15-130=-25t

or

-15-130=-25t

\frac{115}{25}=t

or

\frac{145}{25}=t

This gives us

4.6=t

or

5.8=t

The correct answer is C

ANSWER TO QUESTION 4

Given

P={0,1,2,3,4,56,7,8,9}

and

V={2,4,6,810,1216,18,20}

P\capV={2,4,6,8}

P\V are  elements in P only .

This means that we have to take out the elements of the intersection of the two sets from P.

P\V ={0,1,3,5,5,7,9}

The correct answer is B

ANSWER TO QUESTION 5

The correct answer is B.

In listing the elements of a set, we do not repeat the element. In order words we list only distinct elements.


Blueberry is repeating in both sets but we have to list it once.

ANSWER TO QUESTION 6.

The correct answer is 220

We were told that 250 play basket ball

If 120 play both sports, then

250-120=130

play only basketball

Now the number of people who play only baseball

350-250=100

But the number of people who play baseball

120+100=220

see diagram

7 0
2 years ago
After a number of complaints about its tech assistance, a computer manufacturer examined samples of calls to determine the frequ
icang [17]

Answer:

a) Upper Control Limit = 0.10

   Lower Control Limit = 0.01

b) The tech assistance process is stable and in control.

Step-by-step explanation:

Given - After a number of complaints about its tech assistance, a

            computer manufacturer examined samples of calls to determine

            the frequency of wrong advice given to callers. Each sample

            consisted of 100 calls.

SAMPLE             1   2   3   4   5   6   7   8   9  10 11 12 13 14 15 16

Number of errors 5  3   5   7   4   6   8   4   5    9   3   4   5   6   6   7

To find - a. Determine 95 percent limits.

              b. Is the tech assistance process stable (i.e., in control)

Proof -

z = 95% confidence interval

  = 1.96

⇒z = 1.96

Proportion of defects,P = total defectives/total observations

                                     = 0.0544

⇒P = 0.0544

Now,

Q = 1-P

   = 0.9456

⇒Q = 0.9456

Now,

Average sample size, N = 100

Standard deviation = \sqrt{\frac{P.Q}{N} }

                             = 0.0227

Now,

Upper Control Limit = P + z(Standard deviation)

        = 0.0988

⇒Upper Control Limit = 0.0988 ≈ 0.10

And

Lower Control Limit = P - z(Standard deviation )

       = 0.0099

⇒Lower Control Limit = 0.0099 ≈ 0.01

∴ we get

Upper Control Limit = 0.10

Lower Control Limit = 0.01

b.)

Now,

it is clear that the fraction defective values are wit in upper an lower control limits.

So, The tech assistance process is stable and in control.

5 0
2 years ago
An acute triangle has two sides measuring 8 cm and 10 cm . What is the best representation of the possible range of values for t
Mekhanik [1.2K]

Answer:

the right answer is 2 < s< 18

Step-by-step explanation:

The Third side of the triangle must be greater than the difference of the other two sides which is 10 -8= 2 and smaller than the sum of the other two sides of the triangle which is 10+8= 18.

so third side should be greater than 2 and less than 18.

So right answer is 2 < s< 18

5 0
2 years ago
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