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a_sh-v [17]
2 years ago
13

The Anza-Borrego Desert State Park is one of the best places in the United States for viewing stars. During one 50-day period, c

loud cover obstructed nighttime views just 6% of the time. Based on that sample, how many days a year would you predict that clouds there will interfere with stargazing? Complete the explanation.
Mathematics
1 answer:
likoan [24]2 years ago
4 0

Answer:

22

Step-by-step explanation:

I would assume that the 6% rate would carry for the rest of the year, i.e. all 365 days, 6% of those have clouds interfering with stargazing

365 * 6% = 365 * 0.06 = 21.9, and round up to 22 because you can't really have .9 of a day here.

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Please answer all of them need this
VikaD [51]

First Question

For a better understanding of the solution provided here please find the first attached file which has the diagram of the the isosceles trapezoid.

We dropped perpendiculars from C and D to intersect AB at Q and P respectively.

As can be seen in \Delta BCQ, we can easily find the values of CQ and BQ.

Since, Sin(75^0)=\frac{CQ}{8}

\therefore CQ=8\times Sin(75^0)\approx 7.73 ft

In a similar manner we can find BQ as:

Cos(75^0)=\frac{BQ}{8}

BQ\approx2.07 ft

All these values can be found in the diagram attached.

Thus, because of the inherent symmetry of the isosceles trapezoid, PQ can be found as:

PQ=22-(AP+QB)=22-(2.07+2.07)=17.86

Let us now consider\Delta AQC

We can apply the Pythagorean Theorem here to find the length of the diagonal AC which is the hypotenuse of \Delta AQC.

AC=\sqrt{(AQ)^2+(QC)^2}=\sqrt{(AP+PQ)^2+(QC)^2}=\sqrt{(2.07+17.86)^2+(7.73)^2}\approx21.38 feet.

Thus, out of the given options, Option B is the closest and hence is the answer.

Second Question

For this question we can directly apply the formula for the area of a triangle using sines which is as:

Area=\frac{1}{2}(First Side)(Second Side)(Sine of the angle between the two sides)

Thus, from the given data,

Area=\frac{1}{2}\times 218.5\times 224.5\times sin(58.2^0)\approx20845 m^2

Therefore, Option D is the correct option.

Third Question

For this question we will apply the Sine Rule to the \Delta ABC given to us.

Thus, from the triangle we will have:

\frac{AB}{Sin(\angle C)}=\frac{BC}{Sin(\angle A)}

\frac{c}{Sin(\angle C)}=\frac{a}{Sin(\angle A)}

\frac{17}{Sin(25^0)}=\frac{a}{Sin(45^0)}

This gives a to be:

a\approx28.44

Which is not close to any of the given options.

Fourth Question

Please find the second attachment for a better understanding of the solution provided her.

As can be clearly seen from the attached diagram, we can apply the Cosine Rule here to find the return distance of the plane which is CA.

AC=\sqrt{(AB)^2+(BC)^2-2(AB)(BC)\times Cos(\angle B)}

\therefore AC=\sqrt{(172.20)^2+(111.64)^2-2(172.20)(111.64)\times Cos(177.29^0)}\approx283.8 miles.

Thus, Option D is the answer.





8 0
2 years ago
Read 2 more answers
What is a27 of the sequence 15,10,5,…?
jeka57 [31]

-115

Using the arithmetic formula, your equation appears as so:

an = 15 + (27 - 1) - 5

15 being the first number in the sequence, 27 being the number you're trying to find, and -5 being the common difference.

This will give you the answer of -115.

Hope this helps!

8 0
2 years ago
Radium-226, an isotope of radium, has a half-life of 1,601 years. Suppose your chemistry teacher has a 50-gram sample of radium-
Sholpan [36]
We know that
Half-life is modeled by the formula
An=A0*(0.5)<span>^[t/h)]
where
An----------> </span>is the amount remaining after a time t
A0----------> is the initial quantity
t------------> is the time
h------------> is the half-life of the decaying quantity

in this problem
h=1601 years
A0=50 g
An=?
t=100 years
An=A0*(0.5)^[t/h)]---------> An=50*(0.5)^[100/1601)]-----> 47.88 gr

the answer is 47.88 g
6 0
2 years ago
Read 2 more answers
How many distinct pairs of disjoint non-empty subsets of A are there, the union of which is all of A?
Mrac [35]
A = {1, 2, 5, 6, 8}
{1} U {2, 5, 6, 8} 
{2} U {1, 5, 6, 8} 
{5} U {1, 2, 6, 8} 
{6} U {1, 2, 5, 8} 
{8} U {1, 2, 5, 6} 
{1, 2} U {5, 6, 8} 
{1, 5} U {2, 6, 8} 
{1, 6} U {2, 5, 8}
{1, 8} U {2, 5, 6} 
{1, 2, 5} U {6, 8} 
{1, 2, 6} U {5, 8}
{1, 2, 8} U {5, 6}
{1, 5, 6} U {2, 8}
{1, 5, 8} U {2, 6}
{1, 6, 8} U {2, 5} 
The answer is 15 distinct pairs of disjoint non-empty subsets.
5 0
2 years ago
Mrs.Schroeder, a school principal ,drove her own car for a class trip ,taking a different route . The principal's car can travel
dsp73

Answer:

the principal drove 384 miles

Step-by-step explanation:

12x32=384 miles

3 0
2 years ago
Read 2 more answers
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