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OLEGan [10]
1 year ago
8

Logistic regression is used when you want to: Answer choices A. Predict a dichotomous variable from continuous or dichotomous va

riables. B. Predict a continuous variable from dichotomous variables. C. Predict any categorical variable from several other categorical variables. D. Predict a continuous variable from dichotomous or continuous variables.Logistic regression is used when you want to: Answer choices A. Predict a dichotomous variable from continuous or dichotomous variables. B. Predict a continuous variable from dichotomous variables. C. Predict any categorical variable from several other categorical variables. D. Predict a continuous variable from dichotomous or continuous variables.
Mathematics
1 answer:
masya89 [10]1 year ago
6 0

Answer:

A. Predict a dichotomous variable from continuous or dichotomous variables.

Step-by-step explanation:

Logistic regression is used when you want to predict a dichotomous variable from continuous or dichotomous variables.

Mathematically, it is given by the expression;

Logistic regression y with x_{1}, x_{2}........x_{n}

Where;

y represents the dichotomous dependent variable.

x_{1}, x_{2}........x_{n} represents the predictable variables, which are categorical in nature such as alive or dead, win or lose, sick or healthy, pass or fail, etc.

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Peter has 96 stamps and Sam has 63. How many stamps should Sam give Peter so that Peter will have twice as many stamps as Sam?
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96÷2=48
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The population of Smalltown in the year 1890 was 6,250. Since then, it has increased at a rate of 3.75% each year. • What was th
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Answer:

  • year 1915 :   15,689
  • year 1940 :  39,381

t = 137.9 years

Step-by-step explanation:

Hi, to answer this question we have to apply an exponential growth function:

A = P (1 + r) t  

Where:

p = original population

r = growing rate (decimal form)

t= years

A = population after t years

Replacing with the values given:

A = 6,250 (1 + 3.75/100)^t

A = 6,250 (1 + 0.0375)^t

A = 6,250 (1.0375)^t

  • So, by the year 1915 :

1915-1890 = 25 years passed (t)

A = 6,250 (1.0375)^25

A = 15,689

  • by the year 1940 :

1940-1890 = 50 years passed (t)

A = 6,250 (1.0375)^50

A = 39,381

  • When will the population reach 1,000,000?. We have to subtitute A=1000000 and solve for t.

1,000,000= 6,250 (1.0375)^t

1,000,000/ 6,250 =(1.0375)^t

160 = 1.0375^t

log 160 = log 1.0375^t

log 160 = (t ) log 1.0375

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8 0
1 year ago
-3^(-x)-6=-3^x+10<br><br>Solve the equation below for x by graphing plz
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To graph it, just graph y=-3^{-x}-6 and y=-3^x+10 and see where they intersect

I would like to solve it by using math and not graphing
if you don't want to see the math, just don't scroll down
the graphical meathod is above, first line, just read it

hmm
multiply both sides by -1
3^{-x}+6=3^x-10
multiply both sides by 3^x
3^0+6(3^x)=3^{2x}-10(3^x)
1+6(3^x)=3^{2x}-10(3^x)
minus 1 from both sides and minus 6(3^x) from both sides
0=3^{2x}-16(3^x)-1
use u subsitution
u=3^x
we can rewrite it as
0=u^2-16u-1
now factor
I mean use quadratic formula
for ax^2+bx+c=0 x=\frac{-b+/-\sqrt{b^2-4ac}}{2a}
so for 0=u^2-16u-1, a=1, b=-16, c=-1
u=\frac{-(-16)+/-\sqrt{(-16)^2-4(1)(-1)}{2(1)}
u=8+/-\sqrt{65}
remember that u=3^x so u>0
if we have u=8+√65, it's fine, but u=8-√65 is negative and not allowed
so therfor
u=8+\sqrt{65}=3^x
8+\sqrt{65}=3^x
if you take the log base 3 of both sides you get
log_3(8+\sqrt{65})=x
if you use ln then
ln(8+\sqrt{65})=xln(3)
then
\frac{ln(8+\sqrt{65})}{ln(3)}=x

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