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Ghella [55]
1 year ago
13

What is the value of 3 minus (negative 2)? A number line going from negative 5 to positive 5. –5 –1 1 5What is the product? (6)

(negative 12) –82 –72 72 82
Mathematics
1 answer:
bonufazy [111]1 year ago
4 0

Answer: 5, 72

Step-by-step explanation:

Given the following questions :.

The value of 3 minus (negative 2)

3 - (-2) = 3 + 2 = 5

A number line going from Negative 5 to positive 5, what is the product of 6(negative 12)

6 × (-12) = - 72

Guest
1 year ago
in short words the answer is 5 only5 not -5 5 is th answer
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I assume you mean -x^3 + 4x + 3 
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Suppose that 20% of the adult women in the United States dye or highlight their hair. We would like to know the probability that
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Answer:

71.08% probability that pˆ takes a value between 0.17 and 0.23.

Step-by-step explanation:

We use the binomial approxiation to the normal to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

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The standard deviation of the binomial distribution is:

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Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

p = 0.2, n = 200. So

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\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{200*0.2*0.8} = 5.66

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X = 46

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Z = \frac{46 - 40}{5.66}

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Z = \frac{X - \mu}{\sigma}

Z = \frac{34 - 40}{5.66}

Z = -1.06

Z = -1.06 has a pvalue of 0.1446

0.8554 - 0.1446 = 0.7108

71.08% probability that pˆ takes a value between 0.17 and 0.23.

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