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Luba_88 [7]
2 years ago
8

In a study conducted to examine the quality of fish after 7 days in ice​ storage, ten raw fish of the same kind and approximatel

y the same size were caught and prepared for ice storage. The fish were placed in ice storage at different times after being caught. A measure of fish quality was given to each fish after 7 days in ice storage. Review the accompanying sample data and​ scatterplot, where​ "Time" is the number of hours after being caught that the fish was placed in ice storage and​ "Fish Quality" is the measure given to each fish after 7 days in ice storage​ (higher numbers mean better​ quality). Is it appropriate to use the correlation coefficient to describe the strength of the relationship between​ "Time" and​ "Fish Quality"?

Mathematics
1 answer:
vesna_86 [32]2 years ago
4 0

Question: The sample data and the scatter plot was not added to your question. See the attached file for the scatter plot.

Answer: Yes

Step-by-step explanation:

From scatter plot, it was discovered that there is a linear relationship between the two variables and both variables are quantitative.

Therefore, it appropriate to use the correlation coefficient to describe the strength of the relationship between​ "Time" and​ "Fish Quality"?

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Answer:

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Step-by-step explanation:

The weight of the object in air is 8N,

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8/9.81 = 0.815,

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Upthrust = weight of water displaced = 2N = mass * acceleration

2/9.81 = 0.204kg

density of water(1000kg/m^3) = mass of water / volume of water

volume of water displaced = 0.204/1000 = 0.000204m^3 (204cm^3)

volume of water displaced = volume of the solid

density of solid = mass/ volume = 0.815/0.000204 = 3995.01kg/m^3

b) when fully submerge in water the the scale experience according to newton third law of motion ( equal and opposite reaction of forces) additional 2N push so that total weight with the fully submerge solid = 20N + upthrust = 20N + 2N =22N

c) the of two scale reading is before (8N + 20N = 28N) and after (6N + 22N = 28) since there is no loss of matter; the demonstration was in equilibrium.

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Step-by-step explanation:

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kap26 [50]

Answer:

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Step-by-step explanation:

The diagram below explains the solution better.

From the diagram,

C = starting point of the race.

A = end of the first part of the race.

B = end of the race.

Using Cosine rule, we can find the straight-line distance between the starting point and the end of the race.

Cosine rule states that:

a^2 = b^2 + c^2 - 2bc[cos(A)]

where A = angle A = <A

Given that

b = 5.2 miles

c = 2.0 miles

<A = 115° (from the diagram)

Hence,

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Answer:

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Since the number of items can not be a negative number, we have x ≥ 0 and y ≥ 0.

Condition: He has $36, and can carry up to 20 pounds of food in his backpack.

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If he buys 'x' packs of pasta and 'y' jars of pasta sauce, then:-

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option A: x + 1.5y ≤ 20

option C: x + 3y ≤ 36

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Step-by-step explanation:

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