Answer:
Follows are the solution to this question:
Step-by-step explanation:
Following are the step which is used in the question:
- Step 1, In this use the sheet on the formulas tab we use the function, that is the part of the FLG "Function Library group".
- Step 2, In this step, click the Financial button, and after that click on the PMT.
- Step 3, after clicking on PMT apply or Enter the value that is "B3/12", in this it provides the rate argument box.
- Step 4, after insert value in B4, it provides the Naper argument box, that input the value in "B2" cell into the Pv argument box.
- Step 5, After click the OK button.
Answer:
Due to the higher z-score, David has the higher standardized score
Step-by-step explanation:
Z-score:
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Which student has the higher standardized score
Whoever had the higher z-score.
David:
Scores on Ms. Bond's test have a mean of 70 and a standard deviation of 11. David has a score of 52 on Ms. Bond's test. So 



Steven:
Scores on Ms. Nash's test have a mean of 64 and a standard deviation of 6. Steven has a score of 52 on Ms. So 



Due to the higher z-score, David has the higher standardized score
Answer: 

Step-by-step explanation:
We know that mean and standard deviation of sampling distribution is given by :-


, where
= population mean
=Population standard deviation.
n= sample size .
In the given situation, we have
n= 2
Then, the expected mean and the standard deviation of the sampling distribution will be :_

[Rounded to the nearest whole number]
Hence, the the expected mean and the standard deviation of the sampling distribution :


Jenna's age Jessica's age
today x x + 5
in 5 years x+5
5 years ago x + 5 - 5
Equality x + 5 = x + 5 - 5
=> x + 5 = x
The equation is x + 5 = x
That equation has not any solution, because it reduces to 5 = 0, which is an absurd.
So, the conclusion is that information given by Jenna is wrong.
It is logical: if the difference of the ages is 5, in five years Jenna will have 10 years more than what her sister had 5 years ago, no 5 as she told Jessica.
Answer:
4.43
Step-by-step explanation:
7.90
- 3.47
__________
4. 4 3
I couldn't regroup but of you cross out 0 and put 10, 10-7= 3
and you have to borrow one from 9 and make it 8 and 8-4=4