Answer:
E. P(W | H)
Step-by-step explanation:
What each of these probabilities mean:
P(H): Probability of the game being at home
P(W): Probability of the game being a win.
P(H and W): Probability of the game being at home and being a win.
P(H|W): Probability of a win being at home.
P(W|H): Probability of winning a home game.
Which of the following probabilities do you need to find in order to determine the proportion of at-home games that were wins?
This is the probability of winning a home game. So the answer is:
E. P(W | H)
Given that Roger is building a storage shed with wood blocks that are in the shape of cubic prisms.
cube is basicallye a box which is made of squares. That is all the sides (lenght, width and height) are equal.
Now we have to determine, Can he build a shed that is twice as high as it is wide.
that means if width is 1 then height should be twice which is 2.
yes that is possible if we put one cubical prism over another cubical prism. then height of shed due to two prism will be twice than the width.
Hence correct choice should be "A. Yes. For every block of width, he could build two blocks high."
The answer is
q + d = 12
0.25q + 0.10d = 2.40
q - the number of quarters
d - the number of dimes
You have 12 <span>coins, all quarters and dimes:
q + d = 12
The value of 1 quarter is $0.25.
The value of 1 dime is $0.10.
Therefore, if you want to pay </span>$2.40 you will have q quarters of value $0.25(0.25q) and d dimes of value $0.10d (0.10d).
The second equation is:
0.25q + 0.10d = 2.40
X-intercept has coordinates (x,0)
Y-intercept has coordinates (0,y)
So, the statement "<span> The ordered pair of x-intercept has a zero for the x-value" is false.
</span><span> The ordered pair of x-intercept has a zero for the y-value.</span>
Answer:
The mass of the pipe is 
Step-by-step explanation:
step 1
Find the volume of the steel pipe
The volume is equal to the area of outside circle minus the area of inside circle, multiplied by the length of the pipe
so
![V=\pi [r2^{2}-r1^{2}]L](https://tex.z-dn.net/?f=V%3D%5Cpi%20%5Br2%5E%7B2%7D-r1%5E%7B2%7D%5DL)
we have
---> the radius is half the diameter
---> the radius is half the diameter


substitute
=59.66\ cm^{3}](https://tex.z-dn.net/?f=V%3D%283.14%29%5B1%5E%7B2%7D-0.9%5E%7B2%7D%5D%28100%29%3D59.66%5C%20cm%5E%7B3%7D)
step 2
Find the mass
The mass is equal to the density multiplied by the volume
so
