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sergejj [24]
2 years ago
12

A craftsman can sell 10 jewelry sets for $500 each. He knows

Mathematics
1 answer:
liraira [26]2 years ago
5 0

Answer:15

Step-by-step explanation:

Given

Craftsman sell 10 Jewelry set for $500 each

For each additional set he will decrease the price by $ 25

Suppose he sells n set over 10 set

Earning=\text{Price of each set}\times \text{no of set}

Earning =(500-25n)(10+n)

E=5000+500n-25n^2-250n

differentiate to get the maximum value

\frac{dE}{dn}=-50n+250

Equate \frac{dE}{dn} to get maximum value

-50n+250=0

n=\frac{250}{50}

n=5

Thus must sell 5 extra set to maximize its earnings.

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3x + 3 - 2x = 34

x= 31

(x+1) = 32

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Answer:

C) 0.880

B) 0.075

Step-by-step explanation:

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B.)

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2 years ago
Kiley gathered the data in the table. She found the approximate line of best fit to be y = 1.6x – 4.
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