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zalisa [80]
2 years ago
14

Juan purchased an antique that had a value of $200, at the time of purchase. Each year, the value of the antique is estimated to

increase %10, percent over its value the previous year. The estimated value of the antique, in dollars, 2 years after purchase can be represented by the expression 200a, where a is a constant. What is the value of a ?
Mathematics
1 answer:
algol132 years ago
3 0

Answer: a= 1.21

Step-by-step explanation:

Note: This is a compound interest problem

Step 1

The value of the antique after one year is:

100% + 10% of the purchase price

= 110% of 200

=110/100 of 200

=1.10 × 200

Step 2

The value after two years is:

110% of the value after one year

=110% of (1.10 × 200)

=110/100 of (1.10× 200)

=1.10×(1.10×200)

=1.21×200

Step 3

Expressing the above solutionin the form 200a:

= 200× a = 200 × 1.21

|a=1.21

Thanks

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Answer:

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Step-by-step explanation:

For the random variable N_1 we define the possible values for this variable on this case [1,2,3,4,5] . We know that we have 2 defective transistors so then we have 5C2 (where C means combinatory) ways to select or permute the transistors in order to detect the first defective:

5C2 = \frac{5!}{2! (5-2)!}= \frac{5*4*3!}{2! 3!}= \frac{5*4}{2*1}=10

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P(N_1 = a) = \frac{5-a C 1}{5C2}

For the distribution of N_2 we need to take in count that we are finding a conditional distribution. N_2 given N_1 =a, for this case we see that N_2 \in [1,2,...,5-a], so then exist 5-a C 1 ways to reorder the remaining transistors. And if we want b additional steps to obtain a second defective transistor we have the following probability defined:

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P(N_1 = a , N_2 = b)= \frac{1}{5-a C 1} * \frac{5-a C 1}{5C2} = \frac{1}{5C2}=\frac{1}{10}

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First, you'll need to find the marginal distributions of X,Y. By the law of total probability,

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f_Y(y)=\displaystyle\int_0^yf_{X,Y}(x,y)\,\mathrm dx=\begin{cases}2y&\text{for }0

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