Answer:
Washing cars= 4 hours
Walking dogs= 10 hours
Step-by-step explanation:
You want to start by creating equations. So one thing we know is that he makes $9 an hour washing cars(x) and $8 walking dogs(y).
$9x+$8y=$116
The second Equation is based off of the hours worked. We know that he worked 6 hours more walking the dogs than he did washing cars, so we can take x(being the washing hours) and add 6 to it to equal y (the number of dog hours).
y=x+6
Now You plug what y equals into the first equation to solve for x.
9x+8(x+6)=116 Next distribute the 8 to each term.
9x+8(x)+8(6)=116
9x+8x+48=116 Add the like terms together (9x+8x)
17x+48=116 Subtract the 48 from both sides
-48 -48
17x=68 Now divide by 17 on both sides.
______
17 17
x=4 Finally we can take x and plug it back in to one of the equations in order to solve for y. I'm going to choose the second equation.
y=(4)+6
y=10
Answer:
36
Step-by-step explanation:
if it is two hours then half of it is 9
so 18 + 9 = 27 which is how many miles she biked
6 is the number of miles she ran
so u times it by 1.5
27 + 9 = 36
Answer:
Step-by-step explanation:
51,200 divided by 52. (52 weeks in a year.) 984.615385 is answer. So each week he gets paid $984.62. So then we multiply that by 3 since we are finding 40% of 3 weeks of pay. $984.62x3= $2953.86. Then we multiply that by 40%.. $2953.86x40%= Answer is $11181.54
Answer:
The area of the region between the two curves by integration over the x-axis is 9.9 square units.
Step-by-step explanation:
This case represents a definite integral, in which lower and upper limits are needed, which corresponds to the points where both intersect each other. That is:
Given that resulting expression is a second order polynomial of the form 
, there are two real and distinct solutions. Roots of the expression are:
and 
.
Now, it is also required to determine which part of the interval 
is equal to a number greater than zero (positive). That is:
and 
.
Therefore, exists two sub-intervals: ![[-5, -4.899]](https://tex.z-dn.net/?f=%5B-5%2C%20-4.899%5D)
and ![\left[4.899,5\right]](https://tex.z-dn.net/?f=%5Cleft%5B4.899%2C5%5Cright%5D)
. Besides, 
in each sub-interval. The definite integral of the region between the two curves over the x-axis is:
![A = \int\limits^{-4.899}_{-5} [{1 - (x^{2}-24)]} \, dx + \int\limits^{4.899}_{-4.899} \, dx + \int\limits^{5}_{4.899} [{1 - (x^{2}-24)]} \, dx](https://tex.z-dn.net/?f=A%20%3D%20%5Cint%5Climits%5E%7B-4.899%7D_%7B-5%7D%20%5B%7B1%20-%20%28x%5E%7B2%7D-24%29%5D%7D%20%5C%2C%20dx%20%2B%20%5Cint%5Climits%5E%7B4.899%7D_%7B-4.899%7D%20%5C%2C%20dx%20%2B%20%5Cint%5Climits%5E%7B5%7D_%7B4.899%7D%20%5B%7B1%20-%20%28x%5E%7B2%7D-24%29%5D%7D%20%5C%2C%20dx)
The area of the region between the two curves by integration over the x-axis is 9.9 square units.
Answer:
The correct answer is:option A and B
Step-by-step explanation:
A researcher is studying and examining psychological factors in academic achievement amongst teenage boys. One of the variable he is particularly paying more attention is in determination.
The quantifying of variability for the variable determination suggests how stretched out are the values for determination amid teenage boys (do all boys that are still in their teenage years have the same determination) and how constant are the values of determination amid teenage boys.
