Answer:
<u>The correct answer is A. 16.5%</u>
Step-by-step explanation:
1. Let's review the information given to us to answer the question correctly and to calculate the trend:
2006 2007 Trend
Top Coats 297 223 -24.92%
Parkas 210 210 + 0%
Jackets 213 285 +33.80%
Raincoats 137 259 +89.05
Trench coats 103 127 +23.30%
Total 960 1,104 +15%
2. If the trend shown in these graphs stays constant, what percent of the market will parkas occupy in 2008?
Let's calculate the percent of the market occupied by parkas.
In 2006 = 210/960 = 21.88%
In 2007 = 210/1,104 = 19.02%
In 2008 = 210/1,270 = 16.54% (210 + 0 = 210; 1,104 + 15% = 1,270)
<u>The correct answer is A. 16.5%</u>
The cost of an adult ticket is £6 more than that of a child ticket, so will be denoted by c+6. Now, we are told that the cost of four child tickets and two adult tickets is £40.50, so we can put this in an equation and solve for c:
(c+6)+(c+6)+c+c+c+c=40.50
6c+12=40.50
6c=28.50
c=4.75
Therefore the cost of a child's ticket (c) is £4.75 and the cost of an adult ticket (c+6) is £10.75.
96÷2=48
63-48=15
So Sam should give Peter 15 of his stamps so that Peter will have twice as many stamps as him.
Answer:
The amount of heat required to raise the temperature of liquid water is 9605 kilo joule .
Step-by-step explanation:
Given as :
The mass of liquid water = 50 g
The initial temperature =
= 15°c
The final temperature =
= 100°c
The latent heat of vaporization of water = 2260.0 J/g
Let The amount of heat required to raise temperature = Q Joule
Now, From method
Heat = mass × latent heat × change in temperature
Or, Q = m × s × ΔT
or, Q = m × s × (
-
)
So, Q = 50 g × 2260.0 J/g × ( 100°c - 15°c )
Or, Q = 50 g × 2260.0 J/g × 85°c
∴ Q = 9,605,000 joule
Or, Q = 9,605 × 10³ joule
Or, Q = 9605 kilo joule
Hence The amount of heat required to raise the temperature of liquid water is 9605 kilo joule . Answer
Swimmer a swims 100 meters, which is 100 1-meters, which is 100
(1 yards +3.37 inches) = 100 yards + 337 inches.
1 yard is 3 feet, so 100 yards are 300 feet.
100 in is 8.33 feet so
337 in is (337*8.33)/100=28.07 feet
Swimmer b swims 100 yards, which is 300 feet
Swimmer a swam 28.07 feet.