²⁰¹²C₂₀₁₁ = (2012)! / [(2011)! (2012-2011)!]
²⁰¹²C₂₀₁₁ = (2012)! / [(2011)! (1)!]
Simplify 2012! / (2011)! = 2012
²⁰¹²C₂₀₁₁ = (2012)! / (1)! = 2012
Answer:
The major condition that needs to be satisfied before a t-test is performed that the question satisfies easily is the use of random sampling to obtain sample data.
Step-by-step explanation:
The major conditions necessary to conduct a t-test about a mean include;
- The sample extracted from the population must be extracted using random sampling. That is, the sample must be a random sample of the population.
- The sampling distribution must be normal or approximately normal. This is achievable when the population distribution is normal or approximately normal.
- Each observation in the sample data must have an independent outcome. That is, the outcome/result of each sub-data mustn't depend on one another.
Of the three conditions that need to be satisfied before the conduction of a t-test, the first condition about using a random sampling technique is evidently satisfied.
It is stated in the question that 'A private investigator hired by a competitor takes a random sample of 47 games and tries to determine if there are more than 7 glitches per game'.
Hope this Helps!!!
I don’t understand how to do this
The normal distribution curve is shown in the diagram below
<span>The percentage of time that his commute time exceeds 61 minutes is equal to the area under the standard normal curve that lies to the RIGHT of X=61
Standardising X=61 to find z-score
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from the z-table
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