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Anarel [89]
1 year ago
7

Adante begins to evaluate the expression 3 and one-third times 5 and one-fourth using the steps below. 3 and one-third times 5 a

nd one-fourth 3 and one-third times (5 + one-fourth) (3 and one-third times 5) + (3 and one-third times one-fourth) (3 + one-third) (5) + (3 + one-third) (one-fourth) Which could be his next step?
Mathematics
2 answers:
goldenfox [79]1 year ago
7 0

Answer:

(3)(5) + (1/3)(5) + (3)(1/4) + (1/3)(1/4)

Step-by-step explanation:

(3 1/3)(5 1/4) =

= (3 1/3)(5 + 1/4)

= (3 1/3)(5) + (3 1/3)(1/4)

= (3 + 1/3)(5) + (3 + 1/3)(1/4)

= (3)(5) + (1/3)(5) + (3)(1/4) + (1/3)(1/4)

iren [92.7K]1 year ago
3 0

Answer:

it is a.

Step-by-step explanation:

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The surface areas of two similar solids are 312 ft2 and 1,198 ft2. The volume of the smaller solid is 239 ft3. What is the volum
marin [14]

Answer:

The volume of the larger solid is 1,798\ ft^{3}

Step-by-step explanation:

step 1

Find the scale factor

we know that

If two figures are similar , then the ratio of its surface areas is equal to the scale factor squared

so

Let

z-------> the scale factor

x-------------> surface area larger solid

y-------------> surface area smaller solid

z^{2} =\frac{x}{y}

substitute

z^{2} =\frac{1,198}{312}

z=\sqrt{\frac{1,198}{312}} ----> scale factor

step 2

Find the volume of the larger solid

we know that

If two figures are similar , then the ratio of its volumes is equal to the scale factor elevated to the cube

so

Let

z-------> the scale factor

x-------------> volume of the  larger solid

y-------------> volume of the smaller solid

z^{3}=\frac{x}{y}

we have

z=\sqrt{\frac{1,198}{312}}

y=239\ ft^{3}

substitute the values

(\sqrt{\frac{1,198}{312}}^{3})=\frac{x}{239}

x=239*(\sqrt{\frac{1,198}{312}}^{3})=1,798\ ft^{3}

5 0
1 year ago
Read 2 more answers
The following table shows the number of hours some teachers in two schools expect students to spend on homework each week: Schoo
Lerok [7]

Answer:

For school A: Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17, IQR=9.5

For school B: Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19, IQR=7.5

No, the box plots are not symmetric.

Step-by-step explanation:

Part A

The given data sets are

School A : 9,14,15,17,17,7,15,6,6

School B : 12,8,13,11,19,15,16,5,8

Arrange the data in ascending order.

School A : 6,6,7,9,14,15,15,17,17

School B : 5,8,8,11,12,13,15,16,19

Divide each data set in four equal parts.

School A : (6,6),(7,9),14,(15,15),(17,17)

School B : (5,8),(8,11),12,(13,15),(16,19)

For school A:

Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17

Interquartile range of the data is

IQR=Q_3-Q_1=16-6.5=9.5

For school B:

Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19

Interquartile range of the data is

IQR=Q_3-Q_1=15.5-8=7.5

Part B:

The box plots are not symmetric because the data values are different. Five number summary and IQR of both the data set are different.

4 0
2 years ago
Naomi and her children went into a bakery where they sell donuts for $1.25 each and cookies for $0.75 each. Naomi has $15 to spe
LiRa [457]

Answer:

I dont know the ans can u pls tell me the ans if you get it

4 0
1 year ago
(4 tens 3 ones) x 10
adoni [48]

To solve this problem, we must first convert all of the numbers represented by words into their numeral equivalents so we can simplify. To do this, we must remember that the ones place is the first to the left of the decimal point, and the tens place is one place farther to the left. If we have 4 tens and 3 ones, this is the same as 43 (we put the digit 4 in the tens place and the digit 3 in the ones place). If we replace our words with our new numerical value, we get:

43 * 10

To solve this, we just multiply these two numbers together, which gives us:

430

Therefore, your answer is 430.

Hope this helps!

6 0
1 year ago
Tomio, age 28, takes out $50,000 of straight-life insurance. His annual premium is $418.20. Using the tables found in the textbo
olya-2409 [2.1K]
<span>Tomio, age 28, takes out $50,000 of straight-life insurance. His annual premium is $418.20. Using the tables found in the textbook, determine the cash value of his policy at the end of 20 years. 

A. $26,500
B. $30,000
C. $13,250
D. $26,000

</span>50,000/1,000 = 50 
 265*50 = $13,250

So the cash value of this policy is $13,250
<span>
The correct answer is:
</span><span>C. $13,250</span>
6 0
2 years ago
Read 2 more answers
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