Classify each function as linear or nonlinear.

On a coordinate plane, 2 trapezoids are shown. The first trapezoid has points A (negative 1, 0), B (0, 2), C (3, 2), and D (4, 0

alekssr [168]

Answer:

The answer is D

Step-by-step explanation:

I did the assignment

5 0

2 years ago

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Given: line AB is congruent to line CD and line AD is congruent to line BC. Prove: angle D is congruent to angle B

Taya2010 [7]

AD = BC ----> Parallel lines
AC = AC -----> Reflexive property
<A = <C -----> Congruent angles
<D = <B -----> Congruent angles

8 0

2 years ago

An albatross is a large bird that can fly 400 kilometers in 8 hours at a constant speed. Using d for distance in kilometers and

uranmaximum [27]

We are given relation between distance( in kilometers) travelled and number of hours taken by an Albatross bird.

Distance in kilometers taken by variable d.

Number of hours by t.

And situation is given d=50t.

We know, direct relation formula y= kx read as y is directly proportional to x. And k is the constants of proportionality.

In the given fuction y is taken by variable d and x is taken by variable t.

If we compare d=50t by y = mx, the value of k is 50.

Therefore, constant of proportionality is 50.

Constant is a number that never change it's value.

Therefore, constant of proportionality is just 50.

But we can say variables d and t are two variables those are directly proportional to each other.

Constant of proportionality is actually unit rate of change.

For the given situation constant of proportionality is the number of km travelled in per unit time (in 1 hour.)

If we divide 400km 8 hours, we get 400/8 = 50 km per hour.

Therefore, variables of proporation are d and t and relation between them is " they are directly proportional to each other".

And the constants of proportionality is just 50.

7 0

2 years ago

A sign in the store window advertises 3 t-shirts for $16.50. Which coordinate pair shows the unit rate for the t-shirt sale?

Lerok [7]

16.50/3=5.5 the rate is 5.5.

8 0

2 years ago

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let x = the amoun of raw sugar in tons a procesing plant is a sugar refinery process in one day . suppose x can be model as expo

anygoal [31]

Answer:

The answer is below

Step-by-step explanation:

A sugar refinery has three processing plants, all receiving raw sugar in bulk. The amount of raw sugar (in tons) that one plant can process in one day can be modelled using an exponential distribution with mean of 4 tons for each of three plants. If each plant operates independently,a.Find the probability that any given plant processes more than 5 tons of raw sugar on a given day.b.Find the probability that exactly two of the three plants process more than 5 tons of raw sugar on a given day.c.How much raw sugar should be stocked for the plant each day so that the chance of running out of the raw sugar is only 0.05?

Answer: The mean (μ) of the plants is 4 tons. The probability density function of an exponential distribution is given by:

$f(x)=\lambda e^{-\lambda x}\\But\ \lambda= 1/\mu=1/4 = 0.25\\Therefore:\\f(x)=0.25e^{-0.25x}\\$

a) P(x > 5) = $\int\limits^\infty_5 {f(x)} \, dx =\int\limits^\infty_5 {0.25e^{-0.25x}} \, dx =-e^{-0.25x}|^\infty_5=e^{-1.25}=0.2865$

b) Probability that exactly two of the three plants process more than 5 tons of raw sugar on a given day can be solved when considered as a binomial.

That is P(2 of the three plant use more than five tons) = C(3,2) × [P(x > 5)]² × (1-P(x > 5)) = 3(0.2865²)(1-0.2865) = 0.1757

c) Let b be the amount of raw sugar should be stocked for the plant each day.

P(x > a) = $\int\limits^\infty_a {f(x)} \, dx =\int\limits^\infty_a {0.25e^{-0.25x}} \, dx =-e^{-0.25x}|^\infty_a=e^{-0.25a}$

But P(x > a) = 0.05

Therefore:

$e^{-0.25a}=0.05\\ln[e^{-0.25a}]=ln(0.05)\\-0.25a=-2.9957\\a=11.98$

a ≅ 12

6 0

2 years ago