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inna [77]
2 years ago
13

In the figure, m dbe=50. find each of the following. Please show steps 8.m bed 9.m bea

Mathematics
1 answer:
hammer [34]2 years ago
6 0
Triangle to angle sum theorem.

m<EDB + m<DBE + m<BED = 180
90 + 50 +M<BED = 180
140 + M<BED = 180
-140                  - 140
------------------------------
M<BED = 40
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What is the range of the exponential function shown below
Vsevolod [243]

Answer : y>0

f(x) = 9*2^x

f(x) is an exponential function

f(x) = 9*2^x

When we plug in positive value for x , the value of y is positive

When we plug in negative value for x , the value y is also positive

So for any value of x, the y value is positive always.

Range is the set of y values for which the function is defined

y values are positive , so range is y >0

3 0
2 years ago
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a ball is thrown straight up from the top of a tower that is 280 ft high with an initial velocity of 48 ft/s . the height of the
poizon [28]
First find the time that the ball is level with the top of the building on its descent. You can do this by  solving 280 = -16^2 + 48t + 280 for t. This gives t = 3 seconds . 
Then when the ball reaches the ground the  time t is obtained by solving 0 = -16t^2 + 48t + 280  This gives t = 5.94 seconds.
Answer in interval notation is  (3, 5.94].
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2 years ago
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An element with mass 730 grams decays by 27.6% per minute. How much of the element is remaining after 12 minutes, to the nearest
Korolek [52]
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8 0
2 years ago
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Animals: The label on a bottle of pet vitamins lists dosage guidelines. What dosage would you give to each of these animals? (a)
Salsk061 [2.6K]

Answer:

a) 1 tsp.

b) 1.5 tsp.

c) 2 tsp.

Step-by-step explanation:

Complete Correct Question

Animals: The label on a bottle of pet vitamins lists dosage guidelines. What dosage would you give to each of these animals? (a) a 18 kg adult dog (b) a 6 kg cat (c) 18 kg pregnant dog

- The dosage listed for adult dog is 1/2 tsp per 9 kg dog weight.

- The dosage listed for adult cat is 1/4 tsp per 1 kg weight.

- The dosage listed for pregnant dog is 1/2 tsp per 4.5 kg dog weight.

Solution

a) 18 kg adult dog

The dosage listed for adult dog is 1/2 tsp per 9 kg dog weight.

9 kg dog weight = (1/2) tsp

18 kg adult dog = (18/9) × (1/2) = 1 teaspoon.

b) 6 kg cat

The dosage listed for adult cat is 1/4 tsp per 1 kg weight.

1 kg cat = (1/4) tsp

6 kg cat = (6/1) × (1/4) = (6/4) = 1.5 teaspoons.

c) 18 kg pregnant dog

The dosage listed for pregnant dog is 1/2 tsp per 4.5 kg dog weight.

4.5 kg dog weight = (1/2) tsp

18 kg pregnant dog = (18/4.5) × (1/2) = 2 teaspoons.

Hope this Helps!!!

4 0
2 years ago
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The equation 1.5r + 15 = 2.25r represents the number r of movies you must rent to spend the same amount at each movie store. how
EleoNora [17]
1.5r+15=2.25r
First of all, you have to arrange the numbers according to those similar to them. So that will be;
15=2.25r-1.5r
1.5r is subtracted from 2.25r because it crossed over an equality sign to get its position close to 2.25r. And when a number crosses over an equality sign, the sign on the number chages to the opposite. 1.5r has an invisible positive sign which became negative when it crossed. Anyway;
2.25r-1.5r is the same as 2.25-1.5. And that is 0.75r
  Therefore;
15=0.75r
To find out what r is, you have to divide the both sides by 0.75. This is done to remove the 0.75 close to r to finally reveal what r is. Anyway;
15/0.75=0.75r/0.75
15 divided by 0.75 is 20. And 0.75r divided by  0.75 is r. So;
20=r
r=20. So the answer is 20 movies. Hope i helped. Have a nice day.
4 0
2 years ago
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