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2 years ago

If you have a 40% chance of making a free throw, what is the probability of missing a free throw?

Mathematics

2 answers:

asambeis [7]2 years ago

6 0

The probability of missing a free throw is 60%
100-40=60

Hope this helps

Igoryamba2 years ago

4 0

60% chance of missing a free throw

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Students were asked to write 6x^5 + 8x-3x^3+7x^7 in standard form

WINSTONCH [101]

Answer:

The standard form is $7x^7 +6x^5-3x^3 + 8x$

Step-by-step explanation:

Given:

$6x^5 + 8x-3x^3+7x^7$

To Find :

standard form of $6x^5 + 8x-3x^3+7x^7$

Solution:

A polynomial is in standard form when its term of highest degree is first, its term of 2nd highest is 2nd etc.

In order to write any polynomial in standard form, you look at the degree of each term. You then write each term in order of degree, from highest to lowest, left to write.

Now lets check the degree of each term in the polynomial

The degree of 6x is 5

The degree of 8x is 1

The degree of 3x is 3

The degree of 7x is 7

Now rewrite the polynomial in the order of the degree, from highest to lowest

$7x^7 +6x^5-3x^3 + 8x$

4 0

2 years ago

Enter the values for the highlighted variables to<br> complete the steps to find the sum:

Rina8888 [55]

Answer:

a=-1

b=-9

c=9

d=3

e=3

f=2

g=1.5

Step-by-step explanation:

4 0

2 years ago

K is the midpoint of segment HL . H has coordinates (1, -7 ) , and K has coordinates(-9, 3 ). Find the coordinates of other end

Andrei [34K]

Answer:

Coordinates of other end point L = ( -19, 13 )

Explanation:

The mid point of the coordinates (a,b) and (c,d) is given by $(\frac{a+c}{2},\frac{b+d}{2})$

Here we have (a,b) = (1,-7) and $(\frac{a+c}{2},\frac{b+d}{2})$ = (-9,3) , we need to find (c,d).

$\frac{a+c}{2} =-9\\ \\ 1+c=-18\\ \\ c=-19\\\\ \frac{b+d}{2} =3\\ \\ -7+d=6\\ \\ d=13$

So coordinates of other end point L = ( -19, 13 )

8 0

2 years ago

Read 2 more answers

Given: ΔABC, AC = BC, AB = 3 CD⊥ AB, CD = 3 Find: AC

viva [34]

Answer:

3 $\sqrt{5}$ /2

Step-by-step explanation:

As given, AC = BC, its an isosceles triangle.

Now, CD is perpendicular to AB, therefore AD = DB = 0.5AB = 3/2

Now take triangle ACD,

using Pythagoras theorem,

AC = $\sqrt{AD^{2} + CD^{2} }$

AC = 3 $\sqrt{5}$ /2

:-)

4 0

2 years ago

Read 2 more answers

Pecans that cost $28.50 per kilogram were mixed with almonds that cost $22.25 per kilogram. How many kilograms of each were used

atroni [7]

Answer:

The pecans used in the mixture = 8 kg

The almonds used in the mixture = 17 kg

Step-by-step explanation:

The cost of per kg of pecans = $28.50

The cost of per kg of almonds = $22.25

Now, total weight of mixture = 25 kg

Let us assume the weight of pecans in the mixture = m kg

So, the amount of almonds in the mixture = Total weight - Weight of Pecans

= (25 - m) kg

Now, cost of m kg pecans = m x ( cost of 1 kg pecans) = m x ( $ 28.50)

= 28.50 m

cost of (25- m) kg almonds = (25 -m) x ( cost of 1 kg almonds)

= (25 - m) x ( $ 22.25)

= 556.25 - 22.25 m

Total cost of 25 kg of mixture = 25 x ( $24.25) = $606.25

Now, Total Cost of (almonds + Pecans) = Total cost of mixture

⇒28.50 m + 556.25 - 22.25 m = $606.25

or,6.25 m = 50

or, m = 50/6.25 = 8

Hence, the pecans used in the mixture = m = 8 kg

And the almonds used in the mixture = (25 - m) = 25 - 8 = 17 kg

5 0

2 years ago