Use formula

![\sqrt[3]{27(\cos{330^o}+i\sin{330^o})} \\\sqrt[3]{27e^{i330^o} } \\ \sqrt[3]{27} \sqrt[3]{e^{i330^o}} \\ \sqrt[3]{3^3} \sqrt[3]{e^{i110^o\times 3}} \\ \sqrt[3]{3^3} \sqrt[3]{(e^{i110^o})^ 3}} \\ 3e^{i110^o} \\3(\cos{110^o}+i\sin{110^o})](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27%28%5Ccos%7B330%5Eo%7D%2Bi%5Csin%7B330%5Eo%7D%29%7D%20%0A%5C%5C%5Csqrt%5B3%5D%7B27e%5E%7Bi330%5Eo%7D%20%7D%0A%5C%5C%20%20%5Csqrt%5B3%5D%7B27%7D%20%20%5Csqrt%5B3%5D%7Be%5E%7Bi330%5Eo%7D%7D%20%0A%5C%5C%20%5Csqrt%5B3%5D%7B3%5E3%7D%20%5Csqrt%5B3%5D%7Be%5E%7Bi110%5Eo%5Ctimes%203%7D%7D%20%0A%5C%5C%20%5Csqrt%5B3%5D%7B3%5E3%7D%20%5Csqrt%5B3%5D%7B%28e%5E%7Bi110%5Eo%7D%29%5E%203%7D%7D%20%0A%5C%5C%203e%5E%7Bi110%5Eo%7D%0A%5C%5C3%28%5Ccos%7B110%5Eo%7D%2Bi%5Csin%7B110%5Eo%7D%29)
Since

and

there are two more solutions:
1.

2.
The percentage in increase can be calculated as follows:
% of increase = (difference between new and old amounts / old value) *100
For Dario:
difference in values = 413 - 350 = 63
% of increase = (63/350)*100 = 18%
For Monica:
difference in values = 270 - 225 = 45
% of increase = 20%
Therefore,
Monica has higher percent of increase.
The difference in percents = 20% - 18% = 2%
Answer:
the probability is 78.4%
Step-by-step explanation:
there are 3 scenarios
1) gets the price in the 1st box:
the probability is:
P = probability to obtain a price = 4/10= 40%
2) gets the price in the 2nd box
P= probability to fail in the fist box * probability to obtain a price
P= (6/10)*(4/10)=24/100 = 24%
3) gets the price in the 3rd box
P =probability to fail in the first box * probability to fail in the second box*probability to obtain a price =(6/10)*(6/10)*(4/10)=144/1000 = 14,4%
therefore the probability to obtain a price in 3 or less boxes is:
P = 40%+24%+14.4%= 78.4%
Answer: 0.79
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Answer:
Equation:

Step-by-step explanation:

They sold 45 Hot Beverages and 180 Cold Beverages