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Julli [10]
2 years ago
8

Caleb has 1/3 of a watermelon. He cuts it into 4 equal pieces. What fraction of the watermelon is each piece

Mathematics
2 answers:
Advocard [28]2 years ago
8 0

Answer:

The fraction of the watermelon that corresponds to each piece is \frac{1}{12}

Step-by-step explanation:

Caleb has \frac{1}{3} of a watermelon. To know what fraction each portion of watermelon represents after cutting it into 4 equal parts, just divide the portion that Caleb owns (\frac{1}{3}) by the amount of sliced ​​portions (4):

\frac{\frac{1}{3} }{4}

Given that 4 can also be represented by the fraction \frac{4}{1}, then:

\frac{\frac{1}{3} }{\frac{4}{1} }

To divide two fractions, the SECOND FRACTION must be reversed, that is, change the denominator to the numerator and change the numerator to the denominator. Then, the two fractions are multiplied.

\frac{\frac{1}{3} }{\frac{4}{1} } =\frac{1}{3} *\frac{1}{4} =\frac{1}{12}

<u><em>The fraction of the watermelon that corresponds to each piece is \frac{1}{12}</em></u>

polet [3.4K]2 years ago
5 0

Answer:

1/12 of the watermelon in each piece

Step-by-step explanation:

  1. We must divide 1/3 by 4.
  2. 1/3 divided by 4 is also 1/3 x 1/4.

The final answer is 1/12.



<em>I hope this helped!</em>

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30 were adults and 10 were children :) just add it up
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Katie invested $33,750 at 11.17% compounded continuously.
ser-zykov [4K]

Answer:

Katie's account balance in 10 years will be $3,769,875

Step-by-step explanation:

you multiply the amount of money you invest by the percentage, and the amount of years.

EX: $33,750 × 11.17% × 10= $3,769,875

5 0
2 years ago
A sample of 900 college freshmen were randomly selected for a national survey. Among the survey participants, 372 students were
Rufina [12.5K]

Answer:

a) ME=2.58 \sqrt{\frac{0.413(1-0.413)}{900}}=0.0423

b) 0.413 - 2.58 \sqrt{\frac{0.413(1-0.413)}{900}}=0.371

Step-by-step explanation:

1) Data given and notation  

n=900 represent the random sample taken    

X=372 represent the students were pursuing liberal arts degrees

\hat p=\frac{372}{900}=0.413 estimated proportion of students were pursuing liberal arts degrees

\alpha=0.01 represent the significance level

z would represent the statistic (variable of interest)    

p_v represent the p value (variable of interest)    

p= population proportion of students were pursuing liberal arts degrees

2) Solution to the problem

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 99% confidence interval the value of \alpha=1-0.99=0.01 and \alpha/2=0.005, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=2.58

The margin of error is given by:

ME=z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

If we replace we have:

ME=2.58 \sqrt{\frac{0.413(1-0.413)}{900}}=0.0423

And replacing into the confidence interval formula we got:

0.413 - 2.58 \sqrt{\frac{0.413(1-0.413)}{900}}=0.371

0.413 + 2.58 \sqrt{\frac{0.413(1-0.413)}{900}}=0.455

And the 99% confidence interval would be given (0.371;0.455).

We are confident (99%) that about 37.1% to 45.5% of students were pursuing liberal arts degrees.

7 0
2 years ago
David has twice as many cousins as Becky.
Sonja [21]

Answer:

24 cugini

Step-by-step explanation:

6x2=12

12x2=24

3 0
2 years ago
Read 2 more answers
Problem 5 (4+4+4=12) We roll two fair 6-sided dice. Each one of the 36 possible outcomes is assumed to be equally likely. 1) Fin
tekilochka [14]

Answer:

1

p(b) =  \frac{1}{6}

2

p(k) =  \frac{1}{3}

3

P(a) =  \frac{1}{3}

Step-by-step explanation:

Generally when two fair 6-sided dice is rolled the doubles are

(1 1) , ( 2 2) , (3 3) , (4 4) , ( 5 5 ), (6 6)

The total outcome of doubles is N = 6

The total outcome of the rolling the two fair 6-sided dice is

n = 36

Generally the probability that doubles (i.e., having an equal number on the two dice) were rolled is mathematically evaluated as

p(b) =  \frac{N}{n}

p(b) =  \frac{6}{36}

p(b) =  \frac{1}{6}

Generally when two fair 6-sided dice is rolled the outcome whose sum is 4 or less is

(1, 1), (1, 2), (1, 3), (2, 1), (2, 2), (3, 1)

Looking at this outcome we see that there are two doubles present

So

The conditional probability that doubles were rolled is mathematically represented as

p(k) =  \frac{2}{6}

p(k) =  \frac{1}{3}

Generally when two fair 6-sided dice is rolled the number of outcomes that would land on different numbers is L = 30

And the number of outcomes that at least one die is a 1 is W = 10

So

The conditional probability that at least one die is a 1 is mathematically represented as

P(a) =  \frac{W}{L}

=> P(a) =  \frac{10}{30}

=> P(a) =  \frac{1}{3}

3 0
2 years ago
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