Let m∠CLN = x. Then m∠ALM = 3x, and m∠A = 90°-x, m∠C = 90°-3x.
The sum of angles of ∆ABC is 180°, so we have
... 180° = 40° + m∠A + m∠C
Using the above expressions for m∠A and m∠C, we can write ...
... 180° = 40° + (90° -x) + (90° -3x)
... 4x = 40° . . . . . . . . . add 4x-180°
... x = 10°
From which we conclude ...
... m∠C = 90°-3x = 90° - 3·10° = 60°
The ratio of CN to CL is
... CN/CL = cos(∠C) = cos(60°)
... CN/CL = 1/2
so ...
... CN = (1/2)CL
Answer:
The answer is √44
Step-by-step explanation:
I hope this help.
Determine the slope of line AB
m = 5
Determine the slope of the lines from the options
First option: y = 5x + 3, the slope is 5
Second option: y = (1/5)x + 3, the slope is 1/5
Third option: y = -5x + 3, the slope is -5
Fourth option: y = (-1/5)x + 3, the slope is -1/5
Parallel lines are similar in the slope. So the line which is parallel to line AB must have the slope of 5.
The answer is first option.
She will need 12 seconds because -20•12=-240
Answer:
Vertex form: f(x)=8(x+\frac{1}{4}
Step-by-step explanation:
