Given that:
mean,μ=35.6 min
std deviation,σ=10.3 min
we are required to find the value of x such that 22.96% of the 60 days have a travel time that is at least x.
using z-table, the z-score that will give us 0.2296 is:-1.99
therefore:
z-score is given by:
(x-μ)/σ
hence:
-1.99=(x-35.6)/10.3
-20.497=x-35.6
x=35.6-20.497
x=15.103
Answer:
First look at the number of bricks alone.
Going from 50 bricks to 60 bricks is more work, thus it will require more people. The number of people would be the ratio of the 2. Since the number must be larger, you know the numerator must be the larger of the 2 numbers, so you get 60/50
Next look at the time alone.
Going from 30 minutes to 20 minutes is more work, thus it will require more people. The number of people would be the ratio of the 2. Since the number must be larger, you know the numerator must be the larger of the 2 numbers, so you get 30/20
Now you can just multiply everything.
= 5*60/50*30/20
= 5*6/5*3/2
= 90\10
= 9.
Answer:
9 teams
Step-by-step explanation:
If the total games played was 36 and no team played each other twice, we need to ensure there isn't any double counting.
36 = (n-1) + (n-2) + (n-3) ... + (n-(n-1))
using this knowledge, we can then count up:
1+2+3+4+5+6+7+8 = 36
If our highest number is 8, then we know there must be 9 teams, because no team can play themselves.
Recall that
There are three cases to consider:
(1) When
, we have
and
, so
(2) When
and
, we get
and
, so
(3) When
, we have
and
, so
So
1) From the measure of 40°, you can write:
tan(40°) = 100/x, where x is the base from the building to the tower
⇒x=100/tan(40°) = 119,18 m
2) From the measure of 30°, you can write
tan(30°) = y / 119,18, where y is the height from the roof of Jill's building to the top of the tower.
Then, y = tan(30°) * 119,18 = 68,81 m
3) The height of Jill's building is 100 - 68,81 = 31,19 m
