<u>Given</u>:
Given that a circle O with two tangents BA and BC.
The major arc AC is 234°
The minor arc AC is 126°
We need to determine the measure of ∠ABC
<u>Measure of ∠ABC:</u>
We know the property that, "if a tangent and a secant, two tangents or two secants intersect in the interior of the circle, then the measure of angle formed is one half the difference of the measures of the intercepted arcs."
Hence, applying the above property, we have;
Substituting the values, we get;
Thus, the measure of ∠ABC is 54°
Hence, Option b is the correct answer.
Answer:
The function of the graph is y = 3 cos (4x) ⇒ answer A
Step-by-step explanation:
- If the equation is y = A cos (B x)
* A is the amplitude
- The amplitude is the height from highest to lowest points and
divide the answer by 2
* The period is 2π/B
- The period is the distance from one peak to the next peak
* Lets look to the graph
- The maximum value is 3 and the minimum value is -3
∵ The height from the maximum point to the minimum point is
3 - (-3) = 3 + 3 = 6
∴ The amplitude is 6/2 = 3
∵ A is the amplitude
∴ A = 3
- The distance between two consecutive peaks is π/2
∵ The period is the distance from one peak to the next peak
∴ The period = π/2
∵ The period = 2π/B
∴ 2π/B = π/2 ⇒ divide both sides by π
∴ 2/B = 1/2 ⇒ by using cross multiplication
∴ B = 4
- Lets write the form of the function
∵ y = A cos (Bx)
∵ A = 3 and B = 4
∴ y = 3 cos (4x)
* The function of the graph is y = 3 cos (4x)
Answer:
No the factor of x^2 + 1 = n x^2 + 1
Step-by-step explanation:
To express a function of the form
in vertex form
where (h,k) is the vertex of the parabola, we need to find the vertex first.
To find the vertex we are going to use the vertex formula:
, and
will be the function evaluated at
.
We can infer from our function that
and
. So lets find
:
Now that we have
, we can evaluate the function at 1 to find
:
We have the vertex (1,3) of our parabola, so we can use its vertex form:
We can conclude that the vertex for of our parabola is <span>f(x) = (x + 1)2 + 3.</span>
