Ask question

Ask question

All categories

2 years ago

8

A tennis tournament starts with 117 players. If a player is eliminated after losing three matches, what is the least possible nu

mber of matches played when four players are left?

1 answer:

ahrayia [7]2 years ago

3 0

Step-by-step explanation:

If four players are left, then there are 117 – 4 = 113 players who have been eliminated.

You might be interested in

Can you evaluate (g ○ f)(0)? Explain why or why not.

chubhunter [2.5K]

Answer:

No you can't because just like multiplication, you cant divide anything by zero.

Step-by-step explanation:

You must evaluate the function f first. Division by 0 is undefined.

Therefore, The composition cannot be evaluated.

6 0

2 years ago

Read 2 more answers

Martin is saving for a gaming system. The total cost of the gaming system and three games is $325.49. About how much money shoul

cestrela7 [59]

First you would do $325.49 divided by 20 and you would get $16.27. so you would need $16.27 a week.

4 0

2 years ago

2. The ground below your feet moves at the rate at which

garik1379 [7]

I’m just going off of what I was told in fifth grade, and we were told it was finger nails. Hope this helps!

5 0

2 years ago

Hank bought 3 more boxes of cereal than gallons of milk. He bought x boxes of cereal at $2.79 each. Each

Over [174]

Answer:

true

Step-by-step explanation:

8 0

2 years ago

Exercise 6.12 presents the results of a poll where 48% of 331 Americans who decide to not go to college do so because they canno

tensa zangetsu [6.8K]

<h2>Answer with explanation:</h2>

As per given , we have

$\hat{p}=0.48$ , n=331

Critical value for 90% Confidence interval : $z_{\alpha/2}=1.645$

a) Confidence interval :

$\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

$0.48\pm (1.645)\sqrt{\dfrac{0.48(1-0.48)}{331}}\\\\\approx 0.48\pm0.02746\\\\=(0.48-0.02746,\ 0.48+0.02746)\\\\=(0.45254,\ 0.50746)$

Hence, a 90% confidence interval for the proportion of Americans who decide to not go to college because they cannot a ord it : $(0.45254,\ 0.50746)$

b) Margin of error : E=1.5%=0.015

Formula for sample size : $n=p(1-p)(\dfrac{z_{\alpha/2}}{E})^2$

For p =0.48 , we have

$n=0.48(1-0.48)(\dfrac{1.645}{0.015})^2=3001.88373333\approx3002$

Hence, the required sample size to survey = 3002

6 0

2 years ago