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Pani-rosa [81]
1 year ago
9

Determine the area of squre ABCD with AB=3cm​

Mathematics
2 answers:
Travka [436]1 year ago
8 0

Answer:

Area: 9 cm^{2}

Step-by-step explanation:

Since all sides of a square have equal lengths, the area of the square is a^{2} (a = length of a side).

Since the length of the side of the square is given (is 3cm), the area of the square is (3cm)^{2} =  9cm^{2}

irga5000 [103]1 year ago
8 0

Answer:

9

Step-by-step explanation:

3 by 3 is 9

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After calculating the sample size needed to estimate a population proportion to within 0.05, you have been told that the maximum
Svetlanka [38]

Answer:  40000

Step-by-step explanation:

The formula to find the sample size is given by :-

n=p(1-p)(\dfrac{z_{\alpha/2}}{E})^2, where p is the prior estimate of the population proportion.

Here we can see that the sample size is inversely proportion withe square of margin of error.

i.e. n\ \alpha\ \dfrac{1}{E^2}

By the equation inverse variation, we have

n_1E_1^2=n_2E_2^2

Given : E_1=0.05   n_1=1000

E_2=0.025

Then, we have

(1000)(0.05)^2=n_2(0.025)^2\\\\\Rightarrow\ 2.5=0.000625n_2\\\\\Rightarrow\ n_2=\dfrac{2.5}{0.000625}=4000

Hence, the sample size will now have to be 4000.

6 0
1 year ago
Three of the angles of a polygon are
Liono4ka [1.6K]

Answer:

three angles of a polygon are each 105.5,the sum of the angles in the polygon is 2520. find each of the other angles if they are equal to each other. For a polygon with n sides and n angles, the sum of the measures of all the interior angles equals (n-2)180 degrees. 16-3=13

4 0
2 years ago
Julissa is running a 10-kilometer race at a constant pace. After running for 18 minutes, she completes 2 kilometers. After runni
viktelen [127]

Answer:

the answer is C

Step-by-step explanation:

using her first part 2 kilometers in 18 minutes

total kilometers - 2

and total time - 18

so you would get:

k – 2 = (t – 18)

4 0
1 year ago
Chris’ taxable income is $60,709. She is married, filing jointly. What is her tax?
vitfil [10]
Her tax will be $8,306
7 0
2 years ago
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a perpendicular bisector to is drawn through point c and extended to point d. arrange the pairs of points in order of the y-inte
nirvana33 [79]
Pair 1: slope = (9 - 5)/(8+4) = 1/3
midpoint = ((-4+8)/2, (5+9)/2) = (2, 7)
perpendicular bisector passes through point (2, 7) with slope = -1/(1/3) = -3 giving the equation (y - 7)/(x - 2) = -3 or y - 7 = -3(x - 2) or y = -3x + 13 and y-intercept at y = 13.

Pair 2: slope = (6 - 4)/(-8-2) = -1/5
midpoint = ((2-8)/2, (4+6)/2) = (-3, 5)
perpendicular bisector passes through point (-3, 5) with slope = -1/(-1/5) = 5 giving the equation (y - 5)/(x + 3) = 5 or y - 5 = 5(x + 3) or y = 5x + 20 and y-intercept at y = 20.

Pair 3: slope = (2 - 4)/(7 - 5) = -1
midpoint = ((5+7)/2, (4+2)/2) = (6, 3)
perpendicular bisector passes through point (6, 3) with slope = -1/(-1) = 1 giving the equation (y - 3)/(x - 6) = 1 or y - 3 = (x - 6) or y = x - 3 and y-intercept at y = -3.

Pair 4: slope = (3 - 9)/(-4 - 2) = 1
midpoint = ((2-4)/2, (9+3)/2) = (-1, 6)
perpendicular bisector passes through point (-1, 6) with slope = -1(1) = -1 giving the equation (y - 6)/(x + 1) = -1 or y - 6 = -1(x + 1) or y = -x + 5 and y-intercept at y = 5.

Pair 5: slope = (-12 + 2)/(9 - 3) = -5/3
midpoint = ((3+9)/2, (-2-12)/2) = (6, -7)
perpendicular bisector passes through point (6, -7) with slope = -1(-5/3) = 3/5 giving the equation (y + 7)/(x - 6) = 3/5 or 5(y + 7) = 3(x - 6) or 5y = 3x - 53 and y-intercept at y = -10.6.

Pair 6: slope = (12 - 10)/(8 - 4) = 1/2
midpoint = ((4+8)/2, (10+12)/2) = (6, 11)
perpendicular bisector passes through point (6, 11) with slope = -1(1/2) = -2 giving the equation (y - 11)/(x - 6) = -2 or y - 11 = -2(x - 6) or y = -2x + 23 and y-intercept at y = 23.

Arrangement in order of y-intercepts from smallest to largest
a(3, -2) and b(9, -12)
a(5, 4) and b(7, 2)
a(2, 9) and b(-4, 3)
a(-4, 5) and b(8, 9)
a(2, 4) and b(-8, 6)
a(4, 10) and b(8, 12)

5 0
1 year ago
Read 2 more answers
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