Answer:
<h2>√512 by √512 </h2>
Step-by-step explanation:
Length the length and breadth of the rectangle be x and y.
Area of the rectangle A = Length * breadth
Perimeter P = 2(Length + Breadth)
A = xy and P = 2(x+y)
If the area of the rectangle is 512m², then 512 = xy
x = 512/y
Substituting x = 512/y into the formula for calculating the perimeter;
P = 2(512/y + y)
P = 1024/y + 2y
To get the value of y, we will set dP/dy to zero and solve.
dP/dy = -1024y⁻² + 2
-1024y⁻² + 2 = 0
-1024y⁻² = -2
512y⁻² = 1
y⁻² = 1/512
1/y² = 1/512
y² = 512
y = √512 m
On testing for minimum, we must know that the perimeter is at the minimum when y = √512
From xy = 512
x(√512) = 512
x = 512/√512
On rationalizing, x = 512/√512 * √512 /√512
x = 512√512 /512
x = √512 m
Hence, the dimensions of a rectangle is √512 m by √512 m
The little lines in each side show that the sides are the same length but you also need to find the length of the smaller side which isn’t the same. For this imagine that the shape is split into a square and a triangle and you need to find the long side of the triangle using Pythagoras
a^2 + b^2 = c^2
20^2 + 20^2 = 800
Square root of 800 = 28.3
Then do 28.3-20=8.3
So I think the answer is 20+20+20+20+20+8.3=108.3 cm
The interest due on the first payment is
.. I = Prt
.. I = 110,000*.055*(1/12)
.. I = 504.17
Then the decrease in principal resulting from the first payment is
.. 568.00 -504.17 = 63.83
and the new balance is
.. $110,000.00 -63.83 = $109,936.17
Answer:
she has 12 - D quarters.
She has 24 (12-D) cents in quarters
Step-by-step explanation:
You know that the number of coins, and you know the number of dimes - even if the amount is a variable - you can find the amount of quarters with an equation.
If you knew that Lina had 6 dimes instead of D, you would say 12 - 6 and get the number of quarters. You can do the same thing here.
and If you know Lina has 6 quarters, you could find the amount of money in cents by multiplying 6 by 25. You can do that here too, but with variables and an equation.
You want the answer to be as close to 16 as possible. The answer is C. 15
