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vazorg [7]
2 years ago
14

8.1g of sugar is needed for every cake made. How much sugar is needed for 6 cakes?

Mathematics
1 answer:
Lerok [7]2 years ago
8 0

Answer:

48.6

Step-by-step explanation:

If you use 8.1g of sugar for 1 cake then 6 cakes will be 48.6g of sugar

Just do 8.1*6 and you will get 48.6

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A street lamp casts a shadow 31.5 feet long, while an 8 foot-tall street sign casts a shadow of 14 feet long. What is the length
sergeinik [125]

Answer:

The answer to your question is the height of the lamp is 18.2 ft

Step-by-step explanation:

Data

Street lamp shadow = 31.5 ft

Street sign height = 8 ft

Street sign shadow = 14 ft

Street lamp height = x

Process

1.- To find the height of the lamp use proportions. In this kind of problem, we do not look for the length, but the shadow.

Street lamp height/street lamp shadow = street sign height/street sign

                                                                                                         shadow

Substitution

                                             x / 31.5 = 8 / 14

Solve for x

                                            x = (31.5)(8) / 14

Simplification

                                            x = 254.4 / 14

Result

                                            x = 18.2 ft              

4 0
2 years ago
Cos12sin78+cos78sin12
laila [671]

Answer:

21

Step-by-step explanation:

7 0
2 years ago
Which equation represents a proportional relationship that has a constant of proportionality equal to –10? y = x minus 10 y = x/
kicyunya [14]

Answer:

y=-10x

Step-by-step explanation:

y=-10x

y/x=-10

6 0
2 years ago
If Patricia drives at two-third of her usual speed, she covers a certain distance in one hour more than the time she takes while
zalisa [80]
Let r = usual driving rate
let t = usual driving time
We need to figure out t

The distance she covers in her usual time at her usual rate is r*t

The distance she covers in her new time at her new rate is:
(1+t)*((2/3)r)

Set this equal to each other and solve for t.

rt = (2/3)r + (2/3)rt
(1/3)rt = (2/3)r
(1/3)t = (2/3)
t = 2

So her usual time is 2 hours. (There's probably a faster way to do this)
3 0
2 years ago
In △ABC, m∠A=15 °, a=10 , and b=11 . Find c to the nearest tenth.
pshichka [43]

Answer:

The answer is:

\bold{c\approx 20.2\ units}

Step-by-step explanation:

Given:

In △ABC:

m∠A=15°

a=10 and

b=11

To find:

c = ?

Solution:

We can use cosine rule here to find the value of third side c.

Formula for cosine rule:

cos A = \dfrac{b^{2}+c^{2}-a^{2}}{2bc}

Where  

a is the side opposite to \angle A

b is the side opposite to \angle B

c is the side opposite to \angle C

Putting all the values.

cos 15^\circ = \dfrac{11^{2}+c^{2}-10^{2}}{2\times 11 \times c}\\\Rightarrow 0.96 = \dfrac{121+c^{2}-100}{22c}\\\Rightarrow 0.96 \times 22c= 121+c^{2}-100\\\Rightarrow 21.25 c= 21+c^{2}\\\Rightarrow c^{2}-21.25c+21=0\\\\\text{solving the quadratic equation:}\\\\c = \dfrac{21.25+\sqrt{21.25^2-4 \times 1 \times 21}}{2}\\c = \dfrac{21.25+\sqrt{367.56}}{2}\\c = \dfrac{21.25+19.17}{2}\\c \approx 20.2\ units

The answer is:

\bold{c\approx 20.2\ units}

4 0
2 years ago
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