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nexus9112 [7]
2 years ago
8

A principal of $2000 is placed in a savings account at 3% per annum compounded annually. How much is in the account after one ye

ar, two years and three years?
Mathematics
1 answer:
natita [175]2 years ago
8 0

Answer:

Step-by-step explanation:

After one year

A=p(1+r/n)^nt

=2000(1+0.03/12)^12*1

=2000(1+0.0025)^12

=2000(1.0025)^12

=2000(1.0304)

=$2060.8

After two-years

A=p(1+r/n)^nt

=2060.8(1+0.03/12)^12*2

=2060.8(1+0.0025)^24

=2060.8(1.0025)^24

=2060.8(1.0618)

=$2188.157

After three years

A=p(1+r/n)^nt

=2188.157(1+0.03/12)^12*3

=2188.157(1+0.0025)^36

=2188.157(1.0025)^36

=2188.157(1.0941)

=$2394.063

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Chandra created a budget matrix based on her regular and expected expenses for the year. Expense Jan. Feb. Mar. Apr. May June Ju
Ivan

Answer:

Chandra's Average Monthly Expenses are;

1) For Both Jan and Feb are $269

2) For the remaining 10 months each are $244

Step-by-step explanation:

From Chandra's matrix all monthly expenses are all same that is,

Cell phone $71, Rent $1,025, Gym $75, Internet $25, Auto insurance $425, Gas $ 120, Food $145. which are all the expenses carried out every month for 12 months.

That means Chandra carries out a total of 7 expenses for the month of January and February while she carried a total of 6 expenses for the remaining 10 month which was noted from the matrix that Auto insurance was carried out only in the month of January and February.

Therefore, you start by adding up each month total expenses, which are ;

January = $71 + $1,025 + $75 + $25 + $425 + $120 + $145 = $1886

February = $71 + $1,025 + $75 + $25 + $425 + $120 + $145 = $1886

March = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

April = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

May = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

June = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

July= $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

August = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

September = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

October = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

November = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

December = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

Therefore Chandra's Average Monthly Expenses are:

1) January & February  = \frac{71 + 1,025 + 75 + 25 + 425 + 120 + 145}{7} = \frac{1886}{7} = 269.4286 to the nearest cent

≅ $269

2) For the remaining 10 month are = \frac{71 + 1,025 + 75 + 25  + 120 + 145}{6} = \frac{1461}{6}= 243.5 to the nearest cent

≅ $244

8 0
2 years ago
Read 2 more answers
The local pizza shop sells several special items.
Anna35 [415]

Answer:

Tax for Italian Salad=$0.20

Tax for Lasagna= $0.43

Tax for  Spaghetti =$0.21

Tax for Fettuccini Alfredo   =$0.36

Step-by-step explanation:

Hi, to answer this question we have to multiple the price of each item by the tax percentage in decimal form (divided by 100):

Italian Salad =$3.99  

  • Tax for Italian Salad= 3.99 x (5/100) = 3.99 x 0.05 =$0.20

Lasagna =$8.50  

  • Tax for Lasagna= 8.50 x (5/100) = 8.50 x 0.05 =$0.43

Spaghetti =$4.29  

  • Tax for Spaghetti = 4.29x (5/100) = 4.29 x 0.05 =$0.21

Fettuccini Alfredo =$7.17

  • Tax for Fettuccini Alfredo = 7.17 x (5/100) = 7.17 x 0.05 =$0.36

Feel free to ask for more if needed or if you did not understand something.  

6 0
2 years ago
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A pair of pants costs twice as much as a shirt. The total cost of 1 pair of pants and 1 shirt is $18 . If s represents the cost
dolphi86 [110]

Let the price of 1 shirt be represented by = s

A pair of pants costs twice as much as a shirt, then the cost of pants is = 2s

The total cost of 1 pair of pants and 1 shirt is $18 , means : s+2s=18

Solving this we get,                            

3s=18

s=6

So, the price of 1 shirt is $6 and price of 1 pair of pants is = 2s = 2*6 = $12.

8 0
2 years ago
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What is true about the completely simplified sum of the polynomials 3x2y2 − 2xy5 and −3x2y2 + 3x4y?
svet-max [94.6K]

Answer:

The simplified sum of these polynomials is 3x^4y - 2xy^5

Step-by-step explanation:

In order to find this, we need to remember that we can only add together like terms in this case, there are only two like terms. Both of the first terms end in x^2y^2. So, we add these two together.

3x^2y^2 - 3x^2y^2 = 0

Since they cancel out, we simply just put the other two terms as our answer.

3x^4y - 2xy^5

4 0
2 years ago
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In triangle STU, we have ST = SU = 22 and TU = 8. Let M be the midpoint of <img src="https://tex.z-dn.net/?f=%5Coverline%7BST%7D
dusya [7]

Answer:

4√13  

Step-by-step explanation:

1. Calculate the length of SN

Your triangle (below) is a relatively tall isosceles triangle.

∆STN is a right triangle, so we can use Pythagoras theorem to calculate the length of SN.

SN² + NT² = ST²

SN² + 4² =22²

SN² + 16 = 484

SN² = 468

SN = √468 = 6√13

2. Calculate the length of SX

UM and SN are lines from an angle to the centre of the opposite side, so they are medians.

The medians of a triangle meet at a single point, X — the centroid.

Another characteristic is that the centroid divides each median into segments in a 2:1 ratio.

Thus,

SX = ⅔SN = ⅔ × 6√13 = 4√13

3 0
2 years ago
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