Jayla starts with a population of 100 amoebas that increases 40% every hour for a number of hours, h. The expression 100(1 + 0.4
2 answers:
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Answer:
<em>(–81, 9), (–36, 6), (–1, 1) </em> are the correct three points.
Step-by-step explanation:
Given the function:
Please refer to the attached image.
The green line shows the graph of actual function.
It is reflected over y axis.
The reflected graph is shown in black color in attached image.
When reflected over y axis, the sign of variable changes from Positive to Negative.
So, the resultant function becomes:
i.e. we will have to give the values of x as negative now.
so, the options in which value of x is negative are the possible answers only.
The possible answers are:
(–81, 9), (–36, 6), (–1, 1) and
(–49, 7), (–18, 9), (–1, 1)
Now, we will check the square root function condition.
In the 2nd option, (–18, 9) does not satisfy the condition.
So, the correct answer is:
<em>(–81, 9), (–36, 6), (–1, 1)</em>
Answer:
The amount in the account is $3062.4 (Approx) and compound interest is $162.4 .
Step-by-step explanation:
Formula for compounded semiannually
Where P is the principle , r is the rate in decimal form and t is the time.
As given
Michael arthur deported $2,900 in a new regular savings account that earns 5.5 percent interest .
Here
Principle = $2,900
5.5% is written in the decimal form.
= 0.055
Time = 1 year
Put in the formula
Amount = $ 3062.4 (Approx)
Thus the amount after 1 years is $3062.4 (Approx) .
Now find out the compound interest .
Amount = Principle + Compound interest
Here
Amount = $ 3062.4
Principle = $2,900
Put in the above
$3062.4 = $2,900 + Compound interest
Compound interest = $3062.4 - $2,900
Compound interest = $162.4
Answer:
20,944 years
Step-by-step explanation:
The formula you use for this type of decay problem is the one that uses the decay constant as opposed to the half life in years. We are given the k value of .00012. If we don't know how much carbon was in the bones when the person was alive, it would be safer to say that when he was alive he had 100% of his carbon. What's left then is 8.1%. Because the 8.1% is left over from 100% after t years, we don't need to worry about converting that percent into a decimal. We can use the 8.1. Here's the formula:
where N(t) is the amount left over after the decay occurs, is the initial amount, -k is the constant of decay (it's negative cuz decay is a taking away from as opposed to a giving to) and t is the time in years. Filling in accordingly,
Begin by dividing the 100 on both sides to get
Now take the natural log of both sides. Since the base of a natual log is e, natural logs and e "undo" each other, much like taking the square root of a squared number.
ln(.081)= -.00012t
Take the natual log of .081 on your calculator to get
-2.513306124 = -.00012t
Now divide both sides by -.00012 to get t = 20,944 years