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ozzi
1 year ago
10

A cheese processing company wants to estimate the mean cholesterol content of all one-ounce servings of a type of cheese. The es

timate must be within 0.75 milligrams of the population mean. Determine the minimum sample size required to construct a 95% confidence interval for the population mean. Assume the population standard deviation is 3.10 milligrams
Mathematics
1 answer:
Mrrafil [7]1 year ago
5 0

Answer:

The minimum sample size required to construct a 95% confidence interval for the population mean is 65.

Step-by-step explanation:

We are given the following in the question:

Population standard deviation,

\sigma = 3.10\text{ milligrams}

We need to construct a 95% confidence interval such that the estimate is within 0.75 milligrams of the population mean.

Thus, the margin of error must me 0.75

Formula for margin of error:

z_{critical}\times \dfrac{\sigma}{\sqrt{n}}

z_{critical}\text{ at}~\alpha_{0.05} = 1.96

Putting values, we get,

0.75 = 1.86\times \dfrac{3.10}{\sqrt{n}}\\\\\sqrt{n} = \dfrac{1.96\times 3.10}{0.75}\\\\\sqrt{n} = 8.101\\\Rightarrow n = 65.63\approx 65

Thus, the minimum sample size required to construct a 95% confidence interval for the population mean is 65.

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In April and May of 2011, the Pew Research Center surveyed cell phone users about voice calls and text messaging. They surveyed
sleet_krkn [62]

Answer:

D. We can be 95% confident that the proportion of all cell phone users who use text messaging is between 73.1% and 76.9%.

Step-by-step explanation:

The interpretation of a confidence interval of level x% means that we are x% sure that the interval contains the true mean of the population.

In this problem, we have that:

The population are all the cell phone users.

The 95% confidence interval is (73.1%, 76.9%).

Which of the following is an appropriate interpretation of the 95% confidence interval?

D. We can be 95% confident that the proportion of all cell phone users who use text messaging is between 73.1% and 76.9%.

3 0
1 year ago
During an experiment, Juan rolled a six-sided number cube 18 times. The number two occurred four times. Juan claimed the experim
Maru [420]

Answer:

1) Juans claim is incorrect. The correct experimental probablilty is 2/9

Step-by-step explanation:

8 0
2 years ago
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Which of the following is a point of tangency on the circle below?<br> Help ASAP please
kumpel [21]

Answer:

Point B

Step-by-step explanation:

a point of tangency on a circle is where an outside line touches the outer circle at one point (the outside line touching it only once is what makes that line a tangent) so in this case the point of tangency is Point B

Please mark as Brainliest :)

6 0
2 years ago
In an analysis of healthcare data, ages have been rounded to the nearest multiple of 5 years. The difference between the true ag
Mars2501 [29]

Answer:

The approximate probability that the mean of the rounded ages within 0.25 years of the mean of the true ages is P=0.766.

Step-by-step explanation:

We have a uniform distribution from which we are taking a sample of size n=48. We have to determine the sampling distribution and calculate the probability of getting a sample within 0.25 years of the mean of the true ages.

The mean of the uniform distribution is:

\mu=\dfrac{Max+Min}{2}=\dfrac{2.5+(-2.5)}{2}=0

The standard deviation of the uniform distribution is:

\sigma=\dfrac{Max-Min}{\sqrt{12}}=\dfrac{2.5-(-2.5)}{\sqrt{12}}=\dfrac{5}{3.46}=1.44

The sampling distribution can be approximated as a normal distribution with the following parameters:

\mu_s=\mu=0\\\\\sigma_s=\dfrac{\sigma}{\sqrt{n}}=\dfrac{1.44}{\sqrt{48}}=\dfrac{1.44}{6.93}=0.21

We can now calculate the probability that the sample mean falls within 0.25 from the mean of the true ages using the z-score:

z=\dfrac{X-\mu}{\sigma}=\dfrac{0.25-0}{0.21}=\dfrac{0.25}{0.21}=1.19\\\\\\P(|X_s-\mu|

7 0
2 years ago
A community hall is in the shape of a cuboid the hall is 40m long 15m high and 3m wide. 10 litre paint covers 25m squared costs
krek1111 [17]

Answer:

Total cost for tiles and paints is $924.  

Step-by-step explanation:

We have been given that a community hall is in the shape of a cuboid. The hall is 40m long 15m high and 3m wide.

The paint will be required for 4 walls and ceiling.

Let us find area of walls and ceiling.

\text{Area of walls and ceiling}=(2*40*15)+(2*3*15)+(40*3)

\text{Area of walls and ceiling}=1200+90+120

\text{Area of walls and ceiling}=1410

Therefore, the area of walls and ceiling is 1410 square meters.

Given: Cost for 10 litre of paint is $10 and 10 litre paint covers 25 square meter. Therefore,  

\text{ The total painting cost}=10*(\frac{1410}{25})

\text{ The total painting cost}=10*56.4=564

Therefore, the total painting cost is $564.  

Tiles will be required for floor. Let us find the area of floor.

\text{Area of floor} = 40*3\text{ square meters}

\text{Area of floor} =120\text{ square meters}

Given: 1m squared floor tiles costs $3. So,

\text{Total cost for tiles} = 3*120 = 360

Therefore, the total cost for tiles is $360.  

Now let us find combined total cost of tiles and paint.

\text{Combined total cost}= 564+360 = 924

Therefore, the combined total cost of tiles and paint is $924.

5 0
2 years ago
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